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Aleks04 [339]
3 years ago
15

A fisherman tries to escape a flash flood by walking up the 10 degree hill. If the water is rising at 0.11 m/s, how fast must he

walk to escape the flood?
I will give brainliest. Please do not enter an answer if you do know.
Engineering
2 answers:
FromTheMoon [43]3 years ago
6 0

10.5 mph I’m pretty sure so so sorry if I’m wrong

aleksandr82 [10.1K]3 years ago
6 0
I agree i believe it’s 10.5mp
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Calculate the radius of gyration for a bar of rectangular cross section with thickness t and width w for bending in the directio
SVEN [57.7K]

Answer:

a)R= sqrt( wt³/12wt)

b)R=sqrt(tw³/12wt)

c)R= sqrt ( wt³/12xcos45xwt)

Explanation:

Thickness = t

Width = w

Length od diagonal =sqrt (t² +w²)

Area of raectangle = A= tW

Radius of gyration= r= sqrt( I/A)

a)

Moment of inertia in the direction of thickness I = w t³/12

R= sqrt( wt³/12wt)

b)

Moment of inertia in the direction of width I = t w³/12

R=sqrt(tw³/12wt)

c)

Moment of inertia in the direction of diagonal I= (w t³/12)cos 45=( wt³/12)x 1/sqrt (2)

R= sqrt ( wt³/12xcos45xwt)

4 0
4 years ago
A pipe of 0.3 m outer diameter at a temperature of 160°C is insulated with a material having a thermal conductivity of k = 0.055
Alekssandra [29.7K]

Answer:

Q=0.95 W/m

Explanation:

Given that

Outer diameter = 0.3 m

Thermal conductivity of material

K= 0.055(1+2.8\times 10^{-3}T)\frac{W}{mK}

So the mean conductivity

K_m=0.055\left ( 1+2.8\times 10^{-3}T_m \right )

T_m=\dfrac{160+273+40+273}{2}

T_m=373 K

K_m=0.055\left ( 1+2.8\times 10^{-3}\times 373 \right )

K_m=0.112 \frac{W}{mK}

So heat conduction through cylinder

Q=kA\dfrac{\Delta T}{L}

Q=0.112\times \pi \times 0.15^2\times 120

Q=0.95 W/m

4 0
3 years ago
Does the music contribute to the performance of its production?
gizmo_the_mogwai [7]

Answer:

Of course music plays crucial role

6 0
3 years ago
Someone tell me the answer plz!!DONT be rude and just answer for points:)
Vedmedyk [2.9K]

Answer:

B

Explanation:

B

3 0
3 years ago
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mestny [16]

Answer:

Explanation:

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6 0
3 years ago
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