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Nata [24]
3 years ago
5

What different forms of energy are present when an egg crashes into the egg catcher?

Physics
1 answer:
Sonbull [250]3 years ago
7 0

Answer:

An egg raised above the ground has potential energy due to the force of gravity. When dropped, the egg's potential energy is converted into the kinetic energy of motion. :)

Explanation:

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If you are going 60 mph what is your speed in m per second
LenKa [72]

Answer:

1/60 mps

Explanation:

We would first have to divide 60 by 60 because there is 60mins per hour to get 1mpm. After that we would have to divide 1 by 60 because there are 60 secs in a min. So our final answer after doing 1/60 would be a fraction.

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2 years ago
Modify how could you charge the electric circuit shown below to allow lightbulb a to stay lit even if lightbulb b is removed fro
shepuryov [24]
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5 0
3 years ago
Projectile's horizontal range on level ground is R=v20sin2θ/g. At what launch angle or angles will the projectile land at half o
seraphim [82]

Answer:

\theta = 15^o \: or\: 75^o

Explanation:

As we know that the formula of range is given as

R = \frac{v^2sin2\theta}{g}

now we know that

maximum value of the range of the projectile is given as

R_{max} = \frac{v^2}{g}

now we need to find such angles for which the range is half the maximum value

so we will have

\frac{R}{2} = \frac{v^2}{2g} = \frac{v^2sin(2\theta)}{g}

sin(2\theta) = \frac{1}{2}

2\theta = 30 or 150

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7 0
3 years ago
At the center of the sun, fusion converts hydrogen into
dimaraw [331]
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3 0
3 years ago
A sample of helium has a volume of 12.7 m3. The temperature is raised to 323 K at which time the gas occupies 32.5 m3? Assume pr
jasenka [17]

Answer: The original temperature was

T_{1}=126.51K

Explanation:

Let's put the information in mathematical form:

V_{1}=12.7m^{3}

T_{1}=?

V_{2}=32.5m^{3}

T_{2}=323K

P_{1}=P_{2}=3atm

If we consider the helium as an ideal gas, we can use the Ideal Gas Law:

PV=nRT

were <em>R</em> is the gas constant. And <em>n</em> is the number of moles (which we don't know yet)

From this, taking R=0.08205746\frac{atm.l}{mol.K},  we have:

n=\frac{P_{2}V_{2}}{RT_{2}}

⇒n=3.67mol

Now:

T_{1}=\frac{P_{1}V_{1}}{nR}

⇒T_{1}=126.51K

7 0
3 years ago
Read 2 more answers
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