A compound and/or an moecule
Physical properties are describing the object.
-White
-Small
-Grainy
-Sweet
etc.
339 grams of CLF3 is formed when F2 is in excess and 130 grams of CL2 reacts.
Explanation:
The balanced chemical reaction for the formation of ClF3 is given by:
+ 3 ⇒ 2 Cl
the mass of Cl2 is given 130 grams
From the equation it is found that 2 moles of chloride reacts to form 2 moles of ClF3.
calculating the number of moles of chlorine by the formula:
Number of moles = mass of the substance ÷ atomic mass of one mole of the substance
n = 130 ÷ 35.45
= 3.6671 moles
So, applying stoichiometry
2 moles of Cl2 formed 2 moles of ClF3
3.6671 moles of Cl2 will form x moles of ClF3
2 ÷ 2 = x ÷ 3.6671
x = 3.6671 moles of ClF3
now from the formula of number of moles
weight is calculated as n × mass of the gas
3.6671 × 92.448
= 339.01 grams of ClF3 is formed.
This year course engages students in becoming skilled readers of prose written in a variety of periods, disciplines, and
rhetorical contexts and in becoming skilled writers who compose for a variety of purposes. More immediately, the course
prepares the students to perform satisfactorily on the A.P. Examination in Language and Composition given in the spring.
Both their writing and their reading should make students aware of the interactions among a writer’s purposes, audience
expectations, and subjects as well as the way generic conventions and the resources of language contribute to effectiveness
in writing. Students will learn and practice the expository, analytical, and argumentative writing that forms the basis of
academic and professional writing; they will learn to read complex texts with understanding and to write prose of
sufficient richness and complexity to communicate effectively with mature readers. Readings will be selected primarily,
but not exclusively, from American writers. Students who enroll in the class will take the AP examination.