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ololo11 [35]
2 years ago
11

Help help help plsss

Chemistry
1 answer:
Olin [163]2 years ago
8 0

Answer:

4.58×10^3

3.72×10^7

Explanation:

3.8×10^2 =380

+ 4.2×10^3=4200

= 4580 = 4.58×10^3

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What are 3 pairs of atoms that will connect?​
Alexus [3.1K]

Answer:

<h2>One carbon atom forms four covalent bonds with four hydrogen atoms by sharing a pair of electrons between itself and each hydrogen (H) atom.</h2><h2>...</h2><h2>Properties of polar covalent bond:</h2><h2>Number of electron pairs shared Type of covalent bond formed</h2><h2>1 Single</h2><h2>2 Double</h2><h2>3 Triple</h2>

8 0
2 years ago
Vhat is the molarity of an Nal solution that contains 7.0 g of Nal in 23.0 mL of solution?
Alika [10]

Answer:

Molarity = 5.22 M

Explanation:

Given data:

Mass of sodium chloride = 7.0 g

Volume of solution = 23.0 mL ( 23.0/1000 = 0.023 L)

Molarity = ?

Solution;

Number of moles of NaCl = 7.0 g/ 58.4 g/mol

Number of moles of NaCl = 0.12 mol

Molarity = moles of solute / volume in litter

Molarity = 0.12 mol /  0.023 L

Molarity = 5.22 M

4 0
3 years ago
Select the correct answer.
Burka [1]
C. Tetraphosphorus trisulfide
8 0
2 years ago
How many amps are required to produce 75. 8 g of iron metal from a solution of aqueous iron(iii)chloride in 6. 75 hours?
Shalnov [3]

The amount of current required to produce 75. 8 g of iron metal from a solution of aqueous iron (iii)chloride in 6. 75 hours is 168.4A.

The amount of Current required to deposit a metal can be find out by using The Law of Equivalence. It states that the number of gram equivalents of each reactant and product is equal in a given reaction.

It can be found using the formula,

m = Z I t

where, m = mass of metal deposited = 75.8g

            Z = Equivalent mass / 96500 = 18.6 / 96500 = 0.0001

             I is the current passed

              t is the time taken = 75hour = 75 × 60 = 4500s

On subsituting in above formula,

75.8 = E I t / F

⇒ 75.8 = 0.0001 × I × 4500

⇒ I = 168.4 Ampere (A)

Hence, amount of current required to deposit a metal is 168.4A.

Learn more about Law of Equivalence here, brainly.com/question/13104984

#SPJ4

7 0
1 year ago
What factors are requierd for cloning
ioda
In mammals and amphibians? An enucleated egg, a donor nucleus (preferably from an early developmental stage such as a blastocyst), and a means to stimulate the egg to be activated as if it had just been fertilized (poking with a needle is sometimes enough) 

Or cloning into a vector as in at the level of DNA? 
A vector with positve and negative selection markers (like antibiotic resistance and drug susceptibility), an insert, DNA ligase and restriction enzymes, buffer for restriction and ligation. Or if you are doing cloning by PCR, then you need primers, template, nucleotides, RNA pol like Taq polymerase etc.
8 0
3 years ago
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