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3 years ago

8

Devise a synthetic route from the following starting material to the product. Show all intermediates and reagents. It will requi

re two or more steps.

1 answer:

QveST [7]3 years ago

8 0

Answer:

17292273739374644840hhhh

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You mix 200. mL of 0.400M HCl with 200. mL of 0.400M NaOH in a coffee cup calorimeter. The temperature of the solution goes from

GuDViN [60]

Answer : The enthalpy of neutralization is, 56.012 kJ/mole

Explanation :

First we have to calculate the moles of HCl and NaOH.

$\text{Moles of HCl}=\text{Concentration of HCl}\times \text{Volume of solution}=0.400mole/L\times 0.200L=0.08mol$

$\text{Moles of NaOH}=\text{Concentration of NaOH}\times \text{Volume of solution}=0.400mole/L\times 0.200L=0.08mol$

The balanced chemical reaction will be,

$HCl+NaOH\rightarrow NaCl+H_2O$

From the balanced reaction we conclude that,

As, 1 mole of HCl neutralizes by 1 mole of NaOH

So, 0.08 mole of HCl neutralizes by 0.08 mole of NaOH

Thus, the number of neutralized moles = 0.08 mole

Now we have to calculate the mass of water.

As we know that the density of water is 1 g/ml. So, the mass of water will be:

The volume of water = $200mL+200L=400mL$

$\text{Mass of water}=\text{Density of water}\times \text{Volume of water}=1g/ml\times 400mL=400g$

Now we have to calculate the heat absorbed during the reaction.

$q=m\times c\times (T_{final}-T_{initial})$

where,

q = heat absorbed = ?

$c$ = specific heat of water = $4.18J/g^oC$

m = mass of water = 400 g

$T_{final}$ = final temperature of water = $27.78^oC=273+25.10=300.78K$

$T_{initial}$ = initial temperature of metal = $25.10^oC=273+27.78=298.1K$

Now put all the given values in the above formula, we get:

$q=400g\times 4.18J/g^oC\times (300.78-298.1)K$

$q=4480.96J$

Thus, the heat released during the neutralization = -4480.96 J

Now we have to calculate the enthalpy of neutralization.

$\Delta H=\frac{q}{n}$

where,

$\Delta H$ = enthalpy of neutralization = ?

q = heat released = -4480.96 J

n = number of moles used in neutralization = 0.08 mole

$\Delta H=\frac{-4480.96J}{0.08mole}=-56012J/mole=-56.012kJ/mol$

The negative sign indicate the heat released during the reaction.

Therefore, the enthalpy of neutralization is, 56.012 kJ/mole

8 0

3 years ago

I would really appreciate help with this

Annette [7]

homogeneous: a substance maintaining a uniform appearance throughout.

miscible: the ability of two liquids to be mixed together.

immiscible: two liquids that will not mix with one another.

heterogeneous: a mixture consisting of visibly different substances or phases.

I hope you find this helpful.

8 0

3 years ago

What do transition metals have in common

AVprozaik [17]

Answer: The transition metals have the following physical properties in common: <em><u>they are good conductors of heat and electricity. they can be hammered or bent into shape easily. they have high melting points</u></em> (but mercury is a liquid at room temperature)

Explanation:

5 0

3 years ago

What is the first step in a mass- mole or mass to mass problem?

Sedaia [141]

Mass to mass: moles A x(mole ratio of B/A) and mass to mole: extract the data from the question

4 0

3 years ago

Based on the balanced chemical equation shown below, determine the mass percent of Fe3+ in a 0.6450 g sample of iron ore, if 22.

Genrish500 [490]

Answer:

38.9%

Explanation:

below, determine the mass percent of Fe3+ in a 0.6450 g sample of iron ore, if 22.40 mL of a 0.1000 M stannous chloride, SnCl2(aq), solution is required to completely react with the Fe3+ present in the ore sample. The chemical equation for the reaction is

2 Fe3+ (aq) + Sn2+ (aq) →2Fe2+ (aq) + Snº+(aq).

O 19.40%

O 6.196%

O 38.79%

O 9.697%

2 Fe3+ (aq) + Sn2+ (aq) →2Fe2+ (aq) + Snº+(aq).ole of Sn2+

for every mole of Sn2+, tere are 2 moles of Fe3+

22.4/1000L of 0.1000 M Sn2+ = 22.4 X 0.10/1000 = 0.00224 mole

so there are 0.00224 X 2= 0.00448 moles Fe3+

iron atomic mass is 56

56 X 0.00448 = 0.251 gm Fe3+

so the mass % of the Fe3+ in the 0.645 gm iron ore sample is

(0.251/0.645) X 100 = 38.9%

8 0

3 years ago