Two balls undergo a perfectly elastic head-on collision, with one ball initially at rest. If the incoming ball has a speed of 20
0 m/s . Part APart complete What is the final speed of the incoming ball if it is much more massive than the stationary ball?
2 answers:
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Answer:
(3) 53°
Explanation:
We want to measure the angle that the rains form with the vertical wind shield, so we have to measure the angle relative to the vertical. This means that we can write the following equation
where
is the speed of the rain, which travels vertically
is the speed of the bus, which travels horizontally
Substituting, we find
Answer:
5 x 10⁻⁷N
Explanation:
Given parameters:
Mass of object 1 = 100kg
Mass of object 2 = 300kg
Distance = 2m
Unknown:
Force of gravitational attraction between the objects = ?
Solution:
Newton's law of universal gravitation states that the gravitational force between two bodies is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.
From Newton's law of universal gravitation we derive an expression:
Fg =
G is the universal gravitation constant = 6.67 x 10⁻¹¹
m is the mass
r is the distance between the bodies
Now insert the parameters and solve;
Fg = 6.67 x 10⁻¹¹ x = 5 x 10⁻⁷N