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3 years ago

A stone on the ground has zero energy why

Physics

2 answers:

aniked [119]3 years ago

8 0

Answer:

because the stone is energy to pospurose,mineral,and metaphor

Explanation:

Good luck git's on your paperwork

KatRina [158]3 years ago

7 0

Explanation:

it has no energy when considered with respect to earth ,as it has neither height (i e potential energy) nor velocity (i.e kinetic energy).

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In preparation for the final exam, our astronomy study group has reconvened to discuss Mercury's unique orbital properties. They

grigory [225]

Answer:

The only incorrect statement is from student B

Explanation:

The planet mercury has a period of revolution of 58.7 Earth days and a rotation period around the sun of 87 days 23 ha, approximately 88 Earth days.

Let's examine student claims using these rotation periods

Student A. The time for 4 turns around the sun is

t = 4 88

t = 352 / 58.7 Earth days

In this time I make as many rotations on itself each one with a time to = 58.7 Earth days

#_rotaciones = t / to

#_rotations = 352 / 58.7

#_rotations = 6

therefore this statement is TRUE

student B. the planet rotates 6 times around the Sun

t = 6 88

t = 528 s

The number of rotations on itself is

#_rotaciones = t / to

#_rotations = 528 / 58.7

#_rotations = 9

False, turn 9 times

Student C. 8 turns around the sun

t = 8 88

t = 704 days

the number of turns on itself is

#_rotaciones = t / to

#_rotations = 704 / 58.7

#_rotations = 12

True

The only incorrect statement is from student B

6 0

3 years ago

Starting from rest, an elevator accelerates uniformly between the 1st and 2nd floors, and decelerates uniformly between the 5th

hichkok12 [17]

Answer:

The minimum scale reading during the trip was 560N.

Explanation:

So, in order to solve this problem, we must first prepare a drawing that will represent the situation. (See picture attached)

In the drawing we have the three situations represented. When the elevator goes up, when it travels at a constant velocity and when it decelerates.

We can now do an analysis of each of the situations:

When elevator starts moving:

When the elevator starts moving, it will be accelerated upwards, so the sum of forces will be equal to the mass times the acceleration. In this case, we have two forces, Weight and the normal force, which is the force the floor of the elevator is making upon the scale. This is the reading the scale will give you.

ΣF=ma

-W+N=ma

N=ma+W

As you may see, in this case the weight is added to the force applied by the elevator to accelerate, so the scale reading will be maximum here.

When the elevator has constant velocity:

If the elevator has constant velocity, then its acceleration will be zero, so the sum of the forces will be equal to zero.

ΣF=0

-W+N=0

N=W

On this stage, the scale will return a reading of 800N, since it will not be accelerated.

When the elevator is decelerating:

On the final stage of the trip, the elevator will have a negative acceleration (it is decelerating) so the sum of the forces will be equal to the product between the mass and the acceleration, so we get:

ΣF=-ma

-W+N=-ma

N=W-ma

In this final stage, we can see that the elevator's force is being subtracted from the weight due to the loss of velocity. This is where the scale will give you a minimum reading, so we analyze this stage.

Weight is found by multiplying mass and the acceleration of gravity:

W=mg

so we can rewrite our equation as:

N=mg-ma

when factoring the mass we get:

N=m(g-a)

the mass can be found by dividing the weight into the acceleration of gravity:

W=mg

$m=\frac{W}{g}$

$m=\frac{800N}{10\frac{m}{s^{2}}}$

m=80kg

we know that in the middle of the trip, the elevator will travel 6m in 1s, so the constant velocity is:

$V=\frac{d}{t}$

$V=\frac{6m}{1s}$

$V=6\frac{m}{s}$

this is the initial velocity for the final stage. The acceleration of the final stage can be found with the following formula:

$a=\frac{V_{f}^{2}-V_{0}^{2}}{2x}$

the final velocity is zero since it goes to a stop, so the formula becomes:

$a=\frac{-V_{0}^{2}}{2x}$

when substituting we get:

$a=\frac{-(6m/s)^{2}}{2(6m)}$

$a=-3\frac{m}{s^{2}}$

When substituting values we can now find the scale's reading:

$N=80kg(10m/s^{2}-3m/s^{2})$

$N=80kg(7m/s^{2})$

N=560N

So the minimum scale reading during the trip was 560N

6 0

3 years ago

the air in a tire is initially at 380 kpa, 20 C, when the tire volume is 0.120 m^3. as the tire is warmed by the sun, the pressu

castortr0y [4]

Answer:

final temperature is 364.32 K

mass of air is 0.5423 kg

Explanation:

given data

pressure p1 = 380 kPa

volume v1 = 0.120 m³

temperature = 20°C = 20 + 273 = 293 K

pressure p2 = 3450 kPa

volume v2 = 5% increase

to find out

final temperature and the mass

solution

we consider here ideal gas

so equation is

p1v1 / t1 = p2v2/t2

put here all value and find t2

and v2 is = 0.120 ( 1 + 0.05) = 0.126 m³

t2 = p2v2/ p1v1 × t1

t2 = (450 × 0.126) / (380 × 0.120) × 293

t2 = 364.32 K

so final temperature is 364.32 K

and

mass = p2v2 / Rt2

here R gas constant is 0.287 kJ/kg.K

mass = (450 × 0.126) / (0.287 × 364.32 )

mass = 0.5423

so mass of air is 0.5423 kg

7 0

3 years ago

You are performing an experiment that requires the highest possible energy density in the interior of a very long solenoid. Whic

Alinara [238K]

Answer:

b. increasing the number of turns per unit length on the solenoid

e. increasing the current in the solenoid

Explanation:

As we know that energy density depends on the strength of the magnetic field. The magnetic field strength depends on the no of turns of the solenoid and the current passing through it. The greater the number of turns per unit length, greater the current passing through it, more stronger the magnetic field is. As

B = μ₀nI

n = no of turns

I = current through the wire

So the right options are

b. increasing the number of turns per unit length on the solenoid

e. increasing the current in the solenoid

5 0

4 years ago

Which statement describes the formation of the Milky Way galaxy?

Oliga [24]

Answer:

A disk formed of a long trail of stars coiled into a spiral.

Explanation:

5 0

3 years ago

A stone on the ground has zero energy why​

A stone on the ground has zero energy why