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Alex Ar [27]
3 years ago
8

The products of a combustion reaction include:

Chemistry
1 answer:
aivan3 [116]3 years ago
3 0

Answer:

A

Explanation:

Combustion reactions always produce  water and CO2

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What is the mass of 1 mole of MgSO4?
White raven [17]

Answer:

120.37 g

Explanation:

Mg = 24.31 g

S = 32.06 g

4 O = 16 X 4 = 64 g

Therefore, MgSO4 is (24.31 + 32.06 + 64) g = 120.37 g

7 0
4 years ago
Explain what happens to the heat that is being added to a substance when the substance is changing phase.
nekit [7.7K]
<span>When a substance changes from one state, or phase, of matter to another we say that it has undergone a change of state, or we say that it has undergone a change of phase. For example, ice melts and becomes water; water evaporates and becomes water vapor.These changes of phase always occur with a change of heat. Heat, which is energy, either comes into the material during a change of phase or heat comes out of the material during this change. However, although the heat content of the material changes, the temperature does not.</span>

 

4 0
3 years ago
If 5.1 l of antifreeze solution (specific gravity = 0.80) is added to 3.8 l of water to make a 8.9 l mixture, what is the specif
Maslowich
Density of the mixture = mass of the mixture / volume of the mixture

Mass of the mixture = mass of antifreeze solution + mass of water.

Mass of antifreeze solution = density of the antifreeze solution * volume

Mass of antifreeze solution = 0.8g/ml * 5.1 l * 1000 ml / l = 4,080 g

Mass of water = density of water * volume of water = 1.0 g/ml * 3.8 l * 1000 ml / l = 3,800 g

Mass of mixture = 4080 g + 3800 g= 7880 g

Volume of mixture = volume of antifreeze solution + volume of water

Volume of mixture = 5100 ml + 3800 ml = 8900 ml

Density of mixture = 7800 g / 8900 ml = 0.876 g/ml

Specific gravity of the mixture = density of the mixture / density of water = 0.876

Answer: 0.876
3 0
4 years ago
10 Balance the following equation: + CO2 (g) + H2O (1) → C12H24012 (s) + O2 (g)​
Sveta_85 [38]

Answer:

12CO2 (g) + 12H2O (l) ⇒ C12H24O12 (s) + 12O2

Explanation:

Start by comparing the moles of carbons on the left to number on the right. The number of moles on both side of the arrow should be the same.

8 0
3 years ago
Read 2 more answers
The molar absorptivity of a tyrosine residue at 280 nm is 2000 M-1cm-1, while for tryptophan it is 5500 M-1cm-1. A protein has b
adelina 88 [10]

Answer:

There are 4 tryptophans in the protein.

Explanation:

According to question,  protein contains one tyrosine residue and say x number of tryptophans.

Concentration of protein solution = 1.0 micromolar = 1.0\times 10^{-6} Molar

Molar absorptivity of a protein solution : \epsilon

\epsilon = \epsilon _{tyro}+\epsilon _{tryp}

=1\times 2000 M^{-1}cm^{-1}+x\times 5500 M^{-1}cm^{-1}

Length of the cuvette = l = 1.0 cm

Absorbance of protein solution at 280 nm = A = 0.024

A=\epsilon \times l\times c ( Beer-Lambert's law)

0.024=(1\times 2000 M^{-1}cm^{-1}+x\times 5500 M^{-1}cm^{-1})\times 1 cm\times 1.0\times 10^{-6} M

Solving for x :

x = 4

There are 4 tryptophans in the protein.

7 0
3 years ago
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