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Lana71 [14]
3 years ago
15

A baseball is thrown at a speed of 30.5.if a baseball has a mass of 0.182.what is momentum?

Physics
1 answer:
Oliga [24]3 years ago
3 0

Answer:

p = 5.55 kg-m/s

Explanation:

Given that,

The mass of baseball, m = 0.182 kg

The speed of a baseball, v = 30.5 m/s

We need to find its momentum. The formula for momentum is given by :

p = mv

So,

p = 0.182 kg × 30.5 m/s

p = 5.55 kg-m/s

So, the required momentum is 5.55 kg-m/s.

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Optical tweezers use light from a laser to move single atoms and molecules around. Suppose the intensity of light from the tweez
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a= 4.4×10 m/s^2

Explanation:

pressure P  = E/c

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= 2.22×10^{-6}

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A 10-kg cart moving at 5 m/s collides with a 5-kg cart at rest and causes it to move 10 m/s. Which principle explains the result
Virty [35]

Hello!

A 10-kg cart moving at 5 m/s collides with a 5-kg cart at rest and causes it to move 10 m/s. Which principle explains the result? A) law of differential mass B) law of conservation of momentum C) law of unequal forces D) law of accelerated collision

We have the following data¹:

ΔP (momentum before impact) = ?  

mA (mass) = 10 kg

vA (velocity) = 5 m/s

mB (mass) = 5 kg

vB (velocity) = 0 m/s

Solving:

ΔP = mA*vA + mB*vB

ΔP = 10 kg*5 m/s + 5 kg*0 m/s

ΔP = 50 kg*m/s + 0 kg*m/s

Δp = 50 kg*m/s ← (momentum before impact)

We have the following data²:

ΔP (momentum after impact) = ?  

mA (mass) = 10 kg

vA (velocity) = 0 m/s

mB (mass) = 5 kg

vB (velocity) = 10 m/s

Solving:

Δp = mA*vA + mB*vB

Δp = 10 kg*0 m/s + 5 kg*10 m/s

Δp = 0 kg*m/s + 50 kg*m/s

Δp = 50 kg*m/s ← (momentum after impact)

*** Then, which principle explains the result ?

Law of conservation of momentum, <u>since the total momentum of body A and B before impact is equal to the total momentum of body A and B after impact.</u>

Note:  Bodies of different masses and velocities may have the same kinetic energy, if proportionality between the units is maintained it can occur that they have the same kinetic energy.

Answer:

B) law of conservation of momentum

_______________________

\bf\red{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}\:\:\ddot{\smile}

5 0
3 years ago
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