Answer:
10
Explanation: Earth takes 24 hours to complete one spin, and Mars takes 25 hours. The gas giants rotate really fast. Jupiter takes just 10 hours to complete one rotation. Saturn takes 11 hours, Uranus takes 17 hours, and Neptune takes 16 hours.
Answer:
T²= 4π²R³/GM
Explanation:
First we know that
Fg= Fc
Because centripetal force must equal gravitational force
So
GMm/R² = Mv²/R
But velocity is 2πR/T
So by substitution we have
GMm/R²= M (2πR/T)/T
We have
T²= 4π²R³/GM as period
<span>Using the kinematic equations below, we can calculate the initial velocity required.
Angle of projectile = 60 degrees
Acceleration due to gravity (Ay) = -10 m/s^2 (negative because downward)
Height of projectile (Dy) = 2m
Vfy^2=Voy^2 +2*Ay*Dy
Vfy = 0 m/s because the vertical velocity slows to zero at the height of its trajection.
So... 0 = Voy^2 + 2(-10)(2)
0 = Voy^2 - 40
40 = Voy^2
Sqrt40 = Voy
6.32 m/s = Voy
THIS IS NOT THE ANSWER. THIS IS JUST THE INITIAL VELOCITY IN THE Y DIRECTION.
Using trigonometry, Tan 60 = Voy/Vox. Tan 60 = 6.32/Vox. Vox*Tan 60 = Vox
Vox = 10.95 m/s. Now, using Vox = 10.95 and Voy = 6.32, we can use pythagorean theorem to find the total Vo. A^2 +B^2 = C^2
10.95^2 + 6.32^2 = C^2
Solving for C = 12.64 m/s
This is the velocity required to hit the surface. You can also calculate a bunch of other stuff now using the other kinematic equations.
V = 12.64 m/s</span>
Answer: 
The ball was thrown at the speed of 
.
Maximum height achieved is 
Time of flight is t.
Now, the time the ball takes to achieve maximum height = the time taken by ball to fall back = 
let us just consider the second half of the flight. At , the velocity would be zero. let us consider as the initial velocity for the second half of the flight i.e. 
Using the equation of motion:
where, 
is the final velocity, a is the acceleration, t is the time taken.
Because the ball would fall under gravity, hence a=g and time of flight would be t/2
