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Hatshy [7]
2 years ago
13

An 18.0 g piece of an unidentified metal was heated from 21.5 °C to 89.0 °C. If 789.75 J of heat energy was absorbed by the meta

l in the heating process, what was the identity
of the metal?
Chemistry
1 answer:
nydimaria [60]2 years ago
5 0

Answer: The metal is Calcium.

Explanation:

To calculate the specific heat of substance during the reaction.

q=m\times c\times \Delta T

where,

q = heat absorbed = 789.75 J

c = specific heat of metal = ?

m = mass of substance = 18.0 g

\Delta T_f = final temperature  - initial temperature  = (89.0-21.5)^0C=67.5^0C

Now put all the given values in the above formula, we get:

789.75J=18.0g\times c\times 67.5^0C

c=0.65J/g^0C

As specific heat is characteristic of each metal and thus the metal is calcium which has  specific heat of 0.65J/g^0C

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Earth has one moon and mars has two moons. how many more moons are found around the outer planets than the inner planets?
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