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USPshnik [31]
3 years ago
11

Describe what is wrong with this sentence:

Chemistry
2 answers:
lara [203]3 years ago
7 0

Answer:

hi..,......

.....hsjnsgzgkskshbs

Tresset [83]3 years ago
3 0

Answer:

You transfer kinetic energy from you foot to the ball.

Explanation:

Energy cannot be created or destroyed.

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When aluminum oxidizes in air it forms aluminum oxide (al2o3) if a 51 sheet?
Ede4ka [16]
<span>Answer: mol Al2O3 x 1 mol Al/ 2 mol Al2O3= .25 mol Al The balanced equation tells us that it takes 4 moles of Al to produce 2 moles of Al2O3. 0.50 moles Al2O3 x (4 moles Al / 2 moles Al2O3) = 1.0 moles Al 1.0 moles Al x (27.0 g Al / 1 mole Al) = 27.0 g Al</span>
8 0
4 years ago
Use Hess's law to calculate AG° rxn using the following information.
PIT_PIT [208]

Answer:

AG rxn=+394.4 kJ

Explanation:

3 0
1 year ago
A scientist is observing a cell in notices the presence of starch what does this tell her about the cell
Rom4ik [11]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
Below are the choices the answer is E 

A. It is an animal cell because starch is the energy storing molecule in animal cells. 
<span>B. It is an animal cell because starch is responsible for protein synthesizing in animal cells. </span>
<span>C. It is a plant cell because starch is responsible for protein synthesizing in plant cells. </span>
<span>D. It is a plant cell because starch is responsible for cell building in plant cells. </span>
<span>E. It is a plant cell because starch is the energy storing molecule in plant cells.</span>

5 0
4 years ago
Read 2 more answers
A flashbulb of volume 1.70 mL contains O2(g) at a pressure of 2.30 atm and a temperature of 18.0°C. How many grams of O2(g)
Lady bird [3.3K]

Answer:

0.0001637 mol

Explanation:

PV = nRT

Very important formula in chem

2.3 atm * 0.0017 L = n * 0.082057 * 291 K

= 0.0001637 mol O2

This concept is very important in chem, practice it.

7 0
4 years ago
Calculate the theoretical yield of alum expected from 0.9875 g of aluminum foil. assume the aluminum is the limiting reactant.
skelet666 [1.2K]

Answer: 17.34 grams of alum will be produced if 0.9875 g of Aluminium foil was used.

Explanation: Reaction to form alum from Aluminium is given as:

2Al(s)+2KOH(aq.)+2H_2O(l)+4H_2SO_4(aq.)\rightarrow 2KAl(SO_4)_2(s).12H_2O(l)+3H_2(g)

We are given Aluminium to be the limiting reactant, so the formation of alum will be dependent on Aluminium because it limits the formation of product.

By stoichiometry,

2 moles of Al is producing 2 moles of Alum

Mass of 2 moles of Aluminium = (2 × 27)g/mol = 54 g/mol

Mass of 2 moles of alum = (2 × 474)g/mol = 948 g/mol

54 g/mol of aluminium will produce 948 g/mol of alum, so

\text{0.9875 grams of aluminium will produce}=\frac{948g/mol}{54g/mol}\times 0.9875g

Amount of Alum produced = 17.34 grams

Theoretical yield of alum = 17.34 grams.

5 0
4 years ago
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