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trasher [3.6K]
3 years ago
8

During the plastic deformation portion of a uniaxial compression test, two cylindrical specimens first maintain its cylindrical

shape (decreasing in length and increasing in diameter), then:
a. Specimen 1 transitions into barreling (the specimen attains a barrel shape) and the breaks. b. Specimen 2 breaks without barreling.
Give, in two separate paragraphs with no less than eight (8) lines each, your explanation for these two behaviors.
Engineering
2 answers:
Len [333]3 years ago
5 0

Answer:

points

Explanation:

cluponka [151]3 years ago
5 0

Answer:

i thing the answer is going to be a

Explanation:

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Atoms contain charged particles called___?
solong [7]

Answer:

Answer;

protons and electrons

4 0
3 years ago
A 250-pound person would use a Type 1 ladder even if he were carrying a load with him. true or false
serg [7]

Answer:

The answer is <em>False</em>.

Explanation:

Type 1 ladders have a duty rating of 250-pounds. The fact that the person is carrying a load means that they are exceeding 250 pounds.

Type 1A would be best.

In other words, it's better to be safe than sorry.

<em>Source: Ladder Safety PDF </em>

<em />

-Lexi

8 0
3 years ago
Two identical billiard balls can move freely on a horizontal table. Ball a has a velocity V0 and hits balls B, which is at rest,
Lyrx [107]

Answer:

Velocity of ball B after impact is 0.6364v_0 and ball A is 0.711v_0

Explanation:

v_0 = Initial velocity of ball A

v_A=v_0\cos45^{\circ}

v_B = Initial velocity of ball B = 0

(v_A)_n' = Final velocity of ball A

v_B' = Final velocity of ball B

e = Coefficient of restitution = 0.8

From the conservation of momentum along the normal we have

mv_A+mv_B=m(v_A)_n'+mv_B'\\\Rightarrow v_0\cos45^{\circ}+0=(v_A)_n'+v_B'\\\Rightarrow (v_A)_n'+v_B'=\dfrac{1}{\sqrt{2}}v_0

Coefficient of restitution is given by

e=\dfrac{v_B'-(v_A)_n'}{v_A-v_B}\\\Rightarrow 0.8=\dfrac{v_B'-(v_A)_n'}{v_0\cos45^{\circ}}\\\Rightarrow v_B'-(v_A)_n'=\dfrac{0.8}{\sqrt{2}}v_0

(v_A)_n'+v_B'=\dfrac{1}{\sqrt{2}}v_0

v_B'-(v_A)_n'=\dfrac{0.8}{\sqrt{2}}v_0

Adding the above two equations we get

2v_B'=\dfrac{1.8}{\sqrt{2}}v_0\\\Rightarrow v_B'=\dfrac{0.9}{\sqrt{2}}v_0

\boldsymbol{\therefore v_B'=0.6364v_0}

(v_A)_n'=\dfrac{1}{\sqrt{2}}v_0-0.6364v_0\\\Rightarrow (v_A)_n'=0.07071v_0

From the conservation of momentum along the plane of contact we have

(v_A)_t'=(v_A)_t=v_0\sin45^{\circ}\\\Rightarrow (v_A)_t'=\dfrac{v_0}{\sqrt{2}}

v_A'=\sqrt{(v_A)_t'^2+(v_A)_n'^2}\\\Rightarrow v_A'=\sqrt{(\dfrac{v_0}{\sqrt{2}})^2+(0.07071v_0)^2}\\\Rightarrow \boldsymbol{v_A'=0.711v_0}

Velocity of ball B after impact is 0.6364v_0 and ball A is 0.711v_0.

5 0
3 years ago
In plane stress, a prismatic bar of constant cross-section has an infinite length. a) True b) False
Law Incorporation [45]

Answer:

Option b) False

Explanation:

The given statement for a prismatic bar having constant area of cross section

is not correct and hence False as the length of the bar is not infinite.

The length of the prismatic bar must be very large in comparison to the thickness and width of the bar but has finite length and is not infinite.

Therefore, the correct statement is:

"In plane stress, a prismatic bar with constant area of cross section has finite length."

8 0
3 years ago
Why are there few effective HCI standards?
Oliga [24]

Answer:

<em>There are few effective Human Computer Interaction (HCI) standards because for one, standards are more suitable for hardware than software because they are relatively unstable. ... Some software product standards have been in place long before any formal standard documents were published.</em>

3 0
3 years ago
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