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3 years ago

Determine the total enthalpy of the reactants and the total enthalpy of the products. Record these values in Table C.

Chemistry

1 answer:

Cloud [144]3 years ago

5 0

Answer:

See explanation

Explanation:

The reaction equation is;

C3H8 (g) + 5O2(g) -------> 4H2O(g) + 3CO2(g)

From the formula;

Total enthalpy of reactants = (ΔHf of Reactant 1 x Coefficient) + (ΔHf of Reactant 2 x Coefficient)

Total enthalpy of products= (ΔHf of Product 1 x Coefficient) + (ΔHf of Product 2 x Coefficient)

Hence;

Total enthalpy of reactants =[(-103.85 * 1) + (0 * 5)] = -103.85 + 0 = -103.85 KJ/mol

Total enthalpy of products= [(-393.51 * 4) +(-241.82 * 3)] = (-1574.04) + (-483.64) = -2057.68 KJ/mol

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From the given question;

Fischer projection for an enantiomer of 2-bromo-2,3-dihydroxypropanal with the bromine oriented horizontally to the left and the hydroxide group oriented horizontally to the right.

we can sketch the way the enantiomer of 2-bromo-2,3-dihydroxypropanal can be seen like the one shown below:

CH₂OH

Br -------------|----------------OH

CHO

The objective of this question is to drawn the perspective formula of the molecule.

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