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Dmitry [639]
3 years ago
9

Although we think of land when we hear the word biome, there are also aquatic biomes. The abiotic factors that influence life fo

rms vary with location within ocean systems. Oceanographers divide the ocean into five broad vertical zones as seen in the chart above. Compare the characteristics of the five zones. Where would you expect to find the kelp forest, a type of algae, pictured here and why? A) Algae live in the top two zones in the ocean because light penetrates both zones. B) Algae can live in the three top zones. The abyss is too dark for the algae to survive. C) Algae live only in the epipelagic zone because it is the only zone with enough light for photosynthesis. D) Algae live throughout the five oceans zones because they are the producers that are the base of all food webs.
Chemistry
2 answers:
patriot [66]3 years ago
4 0

The answer is C. Algae live only in the epipelagic zone because it is the only zone with enough light for photosynthesis.

trapecia [35]3 years ago
3 0
The correct option is C.
Kelp are brown large algae, which live in cool, shallow water, close to the shore. Because they depend on light for photosynthesis, they usually inhabit shallow open water and they are found at depths that is not greater than 131 feet.
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When solving a problem it is important to identify your given and needed units, but it is also important to understand the relat
Angelina_Jolie [31]

Answer:

The question has some details missing. here are the details ; Given the following ;  

1. 43.2 g of tablet with 20 cm3 of space

2. 5 cm3 of tablets weighs 10.8 g

3. 5 g of balsa wood with density 0.16 g/cm3

4. 150 g of iron. With density 79g/cm 3

5. 32 cm3 sample of gold with density 19.3 g/cm3

6. 18 ml of cooking oil with density 0.92 g/ml

Explanation:

<u>Appropriate for calculating mass</u>

32 cm3 sample of gold with density 19.3 g/cm3

18 ml of cooking oil with density 0.92 g/ml

<u>Appropriate for calculating volume</u>

5 g of balsa wood with density 0.16 g/cm3

150 g of iron. With density 79g/cm 3

<u>Appropriate for calculating density</u>

43.2 g of tablet with 20 cm3 of space

5 cm3 of tablets weighs 10.8 g

3 0
3 years ago
A gas mixture with 4 mol of Ar, x moles of Ne, and y moles
maks197457 [2]

Answer:

a) \Delta G_{mixing}=\frac{R*T}{12}*[4*ln (1/3) +x*ln (x/12) +(8-x)*ln ((8-x)/12)]

b) x=4

c) \Delta G_{max}=-2721.9 J/mol

Explanation:

Gas mixture:

n_{Ar}= 4 mol

n_{Ne}= x mol

n_{Xe}= y mol

n_{tot}= n_{Ar} + n_{Ne} + n_{Xe}=3*n_{Ar}

n_{Ne} + n_{Xe}=2*n_{Ar}

x + y=8 mol

y=8 mol- x

Mol fractions:

x_{Ar}=\frac{4 mol}{12 mol}=1/3

x_{Ne}=\frac{x mol}{12 mol}=x/12

x_{Xe}=\frac{8 - x mol}{12 mol}=(8-x)/12

Expression of \Delta G_{mixing}

\Delta G_{mixing}=R*T*\sum_{i]*x_i*ln (x_i)

\Delta G_{mixing}=R*T*[1/3*ln (1/3) +x/12*ln (x/12) +(8-x)/12*ln ((8-x)/12)]

\Delta G_{mixing}=\frac{R*T}{12}*[4*ln (1/3) +x*ln (x/12) +(8-x)*ln ((8-x)/12)]

Expression of \Delta G_{max}

\frac{d \Delta G_{mixing}}{dx}=0

\frac{d \Delta G_{mixing}}{dx}=\frac{R*T}{12}*[ln (x/12)+12-ln ((8-x)/12)-12]

0=\frac{R*T}{12}*[ln (x/12)-ln ((8-x)/12)

0=[ln (x/12)-ln ((8-x)/12)

ln (x/12)=ln ((8-x)/12)

x=(8-x)

x=4

\Delta G_{max}=\frac{8.314*298}{12}*[4*ln (1/3) +4*ln (4/12) +(8-4)*ln ((8-4)/12)]

\Delta G_{max}=\frac{8.314*298}{12}*[4*ln (1/3) +4*ln (1/3) +(4)*ln (1/3)]

\Delta G_{max}=\frac{8.314*298}{12}*[12*ln (1/3)]

\Delta G_{max}=-2721.9 J/mol

4 0
3 years ago
I can be found in the 4th period on the periodic table.
Rainbow [258]

Vanadium (V)

Vanadium is the only one in the 4th period here so

4 0
3 years ago
3. Identify the oxidizing agent in each of the fol-
Oxana [17]

Answer:

Cu

Fe

Explanation:

Oxidizing agents:

Oxidizing agents oxidize the other elements and itself gets reduced.

Reducing agents:

Reducing agents reduced the other element are it self gets oxidized.

Oxidation:

Oxidation involve the removal of electrons and oxidation state of atom of an element is increased.

Reduction:

Reduction involve the gain of electron and oxidation number is decreased.

a) Cu²⁺ (aq) + Mg(s) + Cu(s) + Mg²⁺(aq)

Copper is oxidizing agent it accept two electrons from magnesium and oxidize the Mg and itself get reduced.

b) Fe₂O₃(s) + 3CO(g) → 2Fe(l) + 3CO₂(g)​

In this reaction iron is oxidizing agent because iron itself reduced from +3 to 0.

5 0
3 years ago
Determine the mass of 5.20 moles of c6h12
Gwar [14]
Mass is equal to moles x molar mass, and the molar mass of C6H12 is 84, therefore the mass is 436.8 g, but 437 rounded to correct significant figures
5 0
3 years ago
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