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Brut [27]
3 years ago
14

What is the formula to calculate net force

Physics
2 answers:
noname [10]3 years ago
4 0

Answer:

If N is the number of forces acting on a body, the net force formula is given by, FNet = F1 + F2 + F3

Explanation:

kakasveta [241]3 years ago
4 0
If N is the number of forces acting on a body, the net force formula is given by, FNet = F1 + F2 + F3…. + FN.
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In t-ball, young players use a bat to hit a stationary ball off a stand. The 140 g ball has about the same mass as a baseball, b
fomenos

Question is missing. Found on google:

<em>"Part A What is the acceleration of the ball? Express your answer to two significant figures and include the appropriate units. </em>

<em>Part B </em>

<em>What is the net force on the ball during the hit?  </em>

<em>Express your answer to two significant figures and include the appropriate units."</em>

Solution:

A) 6000 m/s^2

The acceleration of the ball is given by

a=\frac{v-u}{t}

where

v = 12 m/s is the final velocity

u = 0 is the initial velocity (the ball is stationary)

t = 2.0 ms = 0.002 s is the time of contact

Substituting,

a=\frac{12-0}{0.002}=6.0 \cdot 10^3 m/s^2

B) 8.4\cdot 10^2 N

The force on the ball can be found by using Newton's second law:

F=ma

where

m = 140 g = 0.14 kg is the mass of the ball

a=6.0\cdot 10^3 m/s^2 is the acceleration

Substituting,

F=(0.14)(6.0\cdot 10^3)=8.4\cdot 10^2 N

3 0
4 years ago
Why does the speed of sound vary depending on the medium through which it travels. in general?
avanturin [10]
Because it is how fast it goes and it depends on the speed
4 0
3 years ago
A spring is 20cm long is stretched to 25cm by a load of 50N. What will be its length when stretched by 100N. assuming that the e
IgorLugansk [536]

Answer:

Final Length = 30 cm

Explanation:

The relationship between the force applied on a string and its stretching length, within the elastic limit, is given by Hooke's Law:

F = kΔx

where,

F = Force applied

k = spring constant

Δx = change in length of spring

First, we find the spring constant of the spring. For this purpose, we have the following data:

F = 50 N

Δx = change in length = 25 cm  - 20 cm = 5 cm = 0.05 m

Therefore,

50 N = k(0.05 m)

k = 50 N/0.05 m

k = 1000 N/m

Now, we find the change in its length for F = 100 N:

100 N = (1000 N/m)Δx

Δx = (100 N)/(1000 N/m)

Δx = 0.1 m = 10 cm

but,

Δx = Final Length - Initial Length

10 cm = Final Length - 20 cm

Final Length = 10 cm + 20 cm

<u>Final Length = 30 cm</u>

6 0
4 years ago
Explain the difference between displacement and distance
alisha [4.7K]
<span>Distance is a scalar quantity that refers to "how much ground an object has covered" during its motion. Displacement is a vector quantity that refers to "how far out of place an object is"; it is the object's overall change in position.</span>
6 0
4 years ago
To practice Problem-Solving Strategy 17.1 for wave interference problems. Two loudspeakers are placed side by side a distance d
Nimfa-mama [501]

Complete Question

The compete question is shown on the first uploaded question

Answer:

The speed is  v  =  350 \  m/s  

Explanation:

From the question we are told that

   The  distance of separation is  d =  4.00 m  

  The distance of the listener to the center between the speakers is  I =  5.00 m

  The change in the distance of the speaker is by k  =  60 cm  =  0.6 \  m

    The frequency of both speakers is f =  700 \  Hz

Generally the distance of the listener to the first speaker is mathematically represented as

       L_1  =  \sqrt{l^2 + [\frac{d}{2} ]^2}

       L_1  =  \sqrt{5^2 + [\frac{4}{2} ]^2}

        L_1  =   5.39 \  m

Generally the distance of the listener to second speaker at its new position is  

          L_2  =  \sqrt{l^2 + [\frac{d}{2} ]^2 + k}

       L_2  =  \sqrt{5^2 + [\frac{4}{2} ]^2 + 0.6}

        L_2  =   5.64  \  m  

Generally the path difference between the speakers is mathematically represented as

        pD  = L_2 - L_1  =  \frac{n  *  \lambda}{2}

Here \lambda is the wavelength which is mathematically represented as

         \lambda =  \frac{v}{f}

=>    L_2 - L_1  =  \frac{n  *  \frac{v}{f}}{2}

=>    L_2 - L_1  =  \frac{n  *  v}{2f}  

=>    L_2 - L_1  =  \frac{n  *  v}{2f}  

Here n is the order of the maxima with  value of  n =  1  this because we are considering two adjacent waves

=>    5.64 - 5.39   =  \frac{1  *  v}{2*700}      

=>    v  =  350 \  m/s  

7 0
4 years ago
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