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scoray [572]
2 years ago
9

What mass of NH3 (g) is produced when 2 x 10^23 molecules of N2 reacts

Chemistry
1 answer:
Ronch [10]2 years ago
7 0

Answer:

m=8.58

Explanation:

n =  \frac{m}{mr}

N=n÷la

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Heat is energy, and that energy would eventually cause the object to undergo a phase change.
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One method of removing phosphate from wastewater effluents is to precipitate it with aluminum sulfate. A plausible stoichiometry
Viktor [21]

Answer: The equation is written below.

Explanation:

2PO_4^{3-}(aq)+Al_2(SO_4)_3(aq)\rightarrow 2AlPO_4(s)+3SO_4^{2-}(aq)

According to Stoichiometry of the reaction:

2 moles of phosphate ions reacts with 1 mole of aluminum sulfate to produce 2 moles of aluminum phosphate precipitate and 3 moles of sulfate ions.

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The chemical equation is written above.

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3 years ago
At 333 k, which of the pairs of gases below would have the most nearly identical rates of effusion?
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8 0
3 years ago
2Fe(s) +3H2SO4(aq) →Fe2(SO4)3(aq) +3H2(g)When 10.3 g of iron are reacted with 14.8 moles of sulfuric acid, what is the percent y
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Answer:

1040%

Explanation:

To solve this question we must convert the mass of Iron to moles in order to find limiting reactant. With limiting reactant we can find the theoretical moles of hydrogen and theoretical mass:

Percent yield = Actual yield (5.40g) / Theoretical yield * 100

<em>Moles Fe -Molar mass: 55.845g/mol-:</em>

10.3g * (1mol / 55.845g) = 0.184 moles of Fe will react.

For a complete reaction of these moles there are necessaries:

0.184 moles Fe* ( 3 mol H2SO4 / 2 mol Fe) = 0.277 moles H2SO4.

As there are 14.8 moles of the acid, <em>Fe is limiting reasctant.</em>

The moles of H2 produced are:

0.184 moles Fe* ( 3 mol H2 / 2 mol Fe) = 0.277 moles H2

The mass is:

0.277 moles H2 * (2.016g/mol) = 0.558g H2

Percent yield is:

5.40g / 0.558g * 100 = 1040%

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