Answer:
As per ASA postulate, the two triangles are congruent.
Step-by-step explanation:
We are given two triangles:
and 
.
AD bisects BE.
AB || DE.
Let us have a look at two properties.
1. When two lines are parallel and a line intersects both of them, then <em>alternate angles </em>are equal.
i.e. AB || ED and 
and 
are alternate angles 
.
2. When two lines are cutting each other, angles formed at the crossing of two, are known as <em>Vertically opposite angles </em>and they are are <em>equal</em>.
Also, it is given that <em>AD bisects BE</em>.
i.e. EC = CB
1.
2. EC = CB
3. 
So, we can in see that in and , two angles are equal and side between them is also equal to each other.
Hence, proved that 
.
Answer:
<em>A ≈ 28.5</em>
Step-by-step explanation:
a, b, c
P = a + b + c
Semiperimeter s = 
A = 
~~~~~~~~~~~~~~~
= 4.3 + 2.89 + 6.81 = 14
s = 14 ÷ 2 = 7
= 
= √14.75901 ≈ 3.84
= 8.59 + 7.58 + 6.81 = 22.98
s = 22.98 ÷ 2 = 11.49
= 
= √609.7343148 ≈ 24.6928
= 3.84 + 24.6928 ≈ <em>28.5</em>
Answer:
21 savage
Step-by-step explanation:
Answer: I'd go with C
Step-by-step explanation:
<h2>
Answer:</h2>
<u>The correct option is 3x + 4y = 10</u>
<h2>
Step-by-step explanation:</h2>
The standard form for any linear equations having two variables is written as Ax+By=C. For example, 3x+4y=10 is a linear equation in standard form. When an equation is given in this form, it becomes easy to find both intercepts (x and y). This form is also very useful when solving systems of two linear equations whose solution is required to find the point of intersection of given lines.
