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3 years ago

The OH- concentration in a 2.5 x 10-3 M Ba(OH)2 solution is

1 answer:

4 0

Answer : C) 5.0 x 10^-3 M
if the concentration of Ba(OH)2 is 2.5 x 10^-3 M

then the OH- concentration is twice this so your answer is C.

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WILL GIVE BRAINLIEST!!!

Rus_ich [418]

Answer:

The answer is B

Explanation:

The answer is B because representative particles can only be atoms.

3 0

3 years ago

Calcium carbonate is often used as an antacid. Your stomach acid is composed of HCl at a pH of 1.5. If you ate toooo much Turkey

stiks02 [169]

Answer: 0.0237 g of calcium carbonate would be required to neutralize the given amount of HCl

Explanation:

pH is defined as the negative logarithm of hydrogen ion concentration present in the solution

$pH=-\log [H^+]$ .....(1)

Given value of pH = 1.5

Putting values in equation 1:

$1.5=-\log[H^+]$

$[H^+]=10^{(-1.5)}=0.0316M$

Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:

$\text{Molarity of solution}=\frac{\text{Number of moles of solute}\times 1000}{\text{Volume of solution (mL)}}$ .....(2)

We are given:

Volume of solution = 15.0 mL

Molarity of HCl = 0.0316 M

Putting values in equation 2:

$0.0316=\frac{\text{Moles of HCl}\times 1000}{15.0}\\\\\text{Moles of HCl}=\frac{0.0316\times 15.0}{1000}=4.74\times 10^{-4}mol$

The chemical equation for the reaction of HCl and calcium carbonate follows:

$2HCl+CaCO_3\rightarrow H_2CO_3+CaCl_2$

By the stoichiometry of the reaction:

2 moles of HCl reacts with 1 mole of calcium carbonate

So, $4.74\times 10^{-4}mol$ of HCl will react with = $\frac{1}{2}\times 4.74\times 10^{-4}=2.37\times 10^{-4}mol$ of calcium carbonate

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of calcium carbonate = $2.37\times 10^{-4}mol$

Molar mass of calcium carbonate = 100.01 g/mol

Putting values in the above equation:

$\text{Mass of }CaCO_3=(2.37\times 10^{-4}mol)\times 100.01g/mol\\\\\text{Mass of }CaCO_3=0.0237g$

Hence, 0.0237 g of calcium carbonate would be required to neutralize the given amount of HCl

7 0

3 years ago

58. A cylinder of a gas mixture used for calibration of blood gas analyzers in medical laboratories contains 5.0% CO2, 12.0% O2,

erica [24]

Answer and Explanation:

$Greetings!$

$Let's~answer~your~question!$

$Partial ~pressure ~of ~gas ~can ~be ~directly~ calculated ~by ~multiplying ~the~ percentage\\ of~ pressure~ of~ gases~ to ~the ~total ~pressure.$

$\boxed{Pgas~ = ~P~total~ * \% ~P ~of ~gas}$

For % of N2 gas: 

 $100\% - (5\% + 12\%) = 83\% ~N2$ 

 $PN_2 ~= ~146~ atm~ *~ 0.83 ~ = 121.18 ~atm$ 

 $PO_2 ~= ~146~ atm~ *~ 0.12~ = 17.52 ~atm$ 

 $~PCO_2~ = ~146~ atm ~* 0.05 = 7.3 ~atm$ 

3 0

4 years ago

How many grams are there in 5.00 moles of lead

Andrew [12]

I wanna say 3,398.08 but let me know if that sounds very off

7 0

3 years ago

During the action of a sodium-potassium pump, 50 ATP molecules were spent. Predict how many sodium ions are transported across t

larisa [96]

Yes, each ATP molecule aids in moving 3 Na+ across the membrane.
so 150 sodium ions are transported across the cell membrane when 50 ATP molecules are spent.

3 0

3 years ago