Answer:
1) When 6.97 grams of sodium(s) react with excess water(l), 56.0 kJ of energy are evolved.
2) When 10.4 grams of carbon monoxide(g) react with excess water(l), 1.04 kJ of energy are absorbed.
Explanation:
1) The following thermochemical equation is for the reaction of sodium(s) with water(l) to form sodium hydroxide(aq) and hydrogen(g).
2 Na(s) + 2H₂O(l) ⇒ 2NaOH(aq) + H₂(g) ΔH = -369 kJ
The enthalpy of the reaction is negative, which means that 369 kJ of energy are evolved per 2 moles of sodium. The energy evolved for 6.97 g of Na (molar mass 22.98 g/mol) is:
2) The following thermochemical equation is for the reaction of carbon monoxide(g) with water(l) to form carbon dioxide(g) and hydrogen(g).
CO(g) + H₂O(l) ⇒ CO₂(g) + H₂(g) ΔH = 2.80 kJ
The enthalpy of the reaction is positive, which means that 2.80 kJ of energy are absorbed per mole of carbon monoxide. The energy evolved for 10.4 g of CO (molar mass 28.01 g/mol) is:
The correct answer among the options given is B. . When
the forward and reverse paths of a change occur at the same rate, <span>the system is in equilibrium specifically in
dynamic equilibrium.<span> Dynamic equilibrium is
the balance in a process that is continuing. </span></span>
Answer:
I. Increasing pressure will allow more frequent successful collision between particles due to the particles being closer together.
II. Rate of reaction increases due to more products being made; as increased pressure favours the exothermic side of the equilibrium.
III. Increasing temperature provides particles lots of (Kinetic) energy, for more frequent successful collision due to the particles moving at a faster rate than before. However, favouring the endothermic side of the equilibrium due to lots of energy required to break and form new bonds.
IV. Rate of reaction increases due to increase temperature favouring both directions of the equilibrium - causing products to form faster.
Hope this helps!
250 kJ/87.9 KJ per mole Cl2 * 71g/mole= 202 g It is D for plato users
Answer:
Option A is correct. About 5 g of the KClO3 is dissolved
Explanation:
KClO3 is not very good soluble in water.
So, Option C is impossible, because KClO3 is poorly soluble in water.
The low solubility of KClO3 in water causes KClO3 to isolate itself from the reaction mixture by precipitating out of solution.
So, option D will either happen.There will be a part of KClO3 dissolve.
At 10 °C, KClO3 has a solubility of 4.46 g/100 gram (10 °C).
Option A is correct. About 5 g of the KClO3 is dissolved
