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RUDIKE [14]
3 years ago
8

Can one mole of peas fit inside your house? List the materials and steps of an experiment that answers the

Chemistry
1 answer:
svlad2 [7]3 years ago
6 0

Answer:

No.

Explanation:

No, one mole of peas do not fit inside a house because one mole is equals to 6.022 × 10²³ units which is a very large value. mole only use for atoms, ions and molecules etc due to very small size but mole is not used for big sized materials such as peas and other vegetables etc. So that's why we can conclude that one mole of peas did not fit inside a house.

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The activation energy of a chemical reaction is the energy that
Svetlanka [38]

Explanation:

The activation energy of a chemical reaction is the amount of energy that must be added to go from the energy level of the reactants to the energy level of transition state.

3 0
3 years ago
A chemist mixes 75.0 g of an unknown substance at 96.5°C with 1,150 g of water at 25.0°C. If the final temperature of the system
AleksAgata [21]
To do this problem it is necessary to take into account that the heat given by the unknown substance is equal to the heat absorbed by the water, but considering the correct sign:

-m\cdot c_e\cdot \Delta T = m_w\cdot c_e_w\cdot \Delta T_w

Clearing the specific heat of the unknown substance:

c_e = \frac{m_w\cdot c_e_w\cdot \Delta T_w}{m\cdot \Delta T} = -\frac{1\ 150\ g\cdot 4.184\frac{J}{g\cdot ^\circ C}\cdot (37.1 - 25.0)^\circ C}{75\ g\cdot (37.1 - 96.5)^\circ C}

c_e = -\frac{1\ 150\ g\cdot 4.184\frac{J}{g\cdot ^\circ C}\cdot 12.1^\circ C}{75\ g\cdot (-59.4)^\circ C} = \bf 13.07\frac{J}{g\cdot ^\circ C}
6 0
3 years ago
Geothermal energy helps to
disa [49]

Answer:A

Explanation:

4 0
3 years ago
Determine the mass of CO2 formed if 15 grams of C4H10
Svetlanka [38]

Answer:

m_{CO_2}=45gCO_2

Explanation:

Hello there!

In this case, since the combustion of butane is:

C_4H_{10}+\frac{13}{2} O_2\rightarrow 4CO_2+5H_2O

Thus, since the molar mass of butane is 58.12 g/mol and that of carbon dioxide is 44.01 g/mol, we obtain the following mass of CO2 product:

m_{CO_2}=15gC_4H_{10}*\frac{1molC_4H_{10}}{58.12gC_4H_{10}} *\frac{4molCO_2}{1molC_4H_{10}} *\frac{44.01gCO_2}{1molCO_2} \\\\m_{CO_2}=45gCO_2

Best regards!

4 0
3 years ago
Calculate the pH in an aqueous 0.120 M nitrous acid solution.
Anvisha [2.4K]

Answer:-  pH is 2.14.

Solution:- Nitrous acid, HNO_2 is a weak acid so first of all we solve for H_3O^+ and then figure out the pH.

the equation is written as:

HNO_2(aq)+H_2O(l)\leftrightharpoons H_3O^+(aq)+NO_2^-(aq)

Initial concentration for the acid is given as 0.120 M. Let's say the change in concentration is x. Then the equilibrium concentrations would be as:

HNO_2=0.120-x

H_3O^+ = x

NO_2^- = x

Ka for nitrous acid is 4.5*10^-^4 and the equilibrium expression for this would be written as:

Ka=\frac{[H_3O^+][NO_2^-]}{HNO_2}

Let's plug in the values in it.

4.5*10^-^4=\frac{(x)^2}{0.120-x}

To make the calculations easy we could ignore x for the bottom and the expression becomes:

4.5*10^-^4=\frac{(x)^2}{0.120}

On cross multiply:

x^2=4.5*10^-^4*0.120

On taking square root to both sides:

x=7.3*10^-^3

So, [H_3O^+]=7.3*10^-^3M

Now we could calculate the pH using the pH formula:

pH=-log[H_3O^+]

pH=-log(7.3*10^-^3)

pH = 2.14

So, the pH of 0.120M nitrous acid is 2.14.

8 0
3 years ago
Read 2 more answers
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