What does a catalyst do when added to a chemical reaction? Select all that apply.
2 answers:
Answer:
Explanation:
A catalyst is a substance that <u>increases the rate</u> of a chemical reaction. Some examples are enzymes and acid-base catalysts.
They can do this by <u>lowering activation energy</u> (the energy needed to undergo a reaction) or modifying a certain mechanism in the reaction.
Catalysts are unique because they aren't consumed or used up in a reaction. They can be reused many times.
So, based on the information above, catalysts do not increase the activation energy or get consumed in the reaction. That leaves two correct answers: they lower the activation energy and speed up chemical reactions.
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Answer : The volume of the gas remaining is 56.5 liters.
The gas is hydrochloric acid and the formula of the gas is HCl.
The mass of produced is, 110.7 grams.
Explanation :
The balanced chemical reaction will be:
First we have to calculate the moles of and HCl
Molar mass of NH_3 = 17 g/mole
and,
Molar mass of HCl = 36.5 g/mole
Now we have to calculate the limiting and excess reagent.
From the balanced reaction we conclude that
As, 1 mole of HCl react with 1 mole of
So, 2.07 mole of HCl react with 2.07 mole of
From this we conclude that, is an excess reagent because the given moles are greater than the required moles and HCl is a limiting reagent and it limits the formation of product.
The remaining moles of HCl gas = 4.44 - 2.07 = 2.37 moles
Now we have to calculate the volume of the gas remaining.
Using ideal gas equation :
PV = nRT
where,
P = Pressure of gas = 752 mmHg = 0.989 atm (1 atm = 760 mmHg)
V = Volume of gas = ?
n = number of moles of gas = 2.37 moles
R = Gas constant = 0.0821 L.atm/mol.K
T = Temperature of gas =
Putting values in above equation, we get:
V = 56.5 L
Now we have to calculate the moles of
As, 1 mole of HCl react with 1 mole of
So, 2.07 mole of HCl react with 2.07 mole of
Now we have to calculate the mass of
Molar mass of = 53.5 g/mole
Thus, the volume of the gas remaining is 56.5 liters.
The gas is hydrochloric acid and the formula of the gas is HCl.
The mass of produced is, 110.7 grams.
Answer:
The reaction when the Borane (BH3) is add to an alkene and form an alkylborane is shown below.
Explanation:
The boron of the borane does not have extra electron pairs, in this way the double bond of the alkene attacks the boron and the hydrogen belonging to the borane adheres to the carbon that is more substituted, thus forming an alkyl borane.
