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3 years ago

An unbalanced force is at work when

Physics

2 answers:

kogti [31]3 years ago

7 0

I would go with C because all the rest of the answer are sitting on something.

madam [21]3 years ago

7 0

ANSWER:(C) definitely when a model rocket takes off!!
,Thank you

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Find the magnitude of a fourth force on the stone that will make the vector sum of the four forces zero.

Tanya [424]

100cos30° + 80cos120° + 40cos233° + Dx = 0
Dx = -22.53 N 

y components: 
100sin30° + 80sin120° + 40sin233° + Dy = 0 
Dy = -87.34 N 

magnitude of D: 
sqrt[(-22.53)² + (-87.34)²] 
90.2 N 

direction of D: 
arctan[(-87.34)/(-22.53)] 
75.5° ref, but since Dx and Dy are both negative, we know this vector is in QIV: 
360 - 75.5° = 284.5°

7 0

3 years ago

Indiana Jones is in a temple searching for artifacts. He finds a gold sphere with a radius of 2 cm sitting on a pressure sensiti

Vlad1618 [11]

Answer:

Volume of Sand = 0.4 m³

Radius of Sand Sphere = 0.46 m

Explanation:

First we need to find the volume of gold sphere:

Vg = (4/3)πr³

where,

Vg = Volume of gold sphere = ?

r = radius of gold sphere = 2 cm = 0.02 m

Therefore,

Vg = (4/3)π(0.2 m)³

Vg = 0.0335 m³

Now, we find mass of the gold:

ρg = mg/Vg

where,

ρg = density of gold = 19300 kg/m³

mg = mass of gold = ?

Vg = Volume of gold sphere = 0.0335 m³

Therefore,

mg = (19300 kg/m³)(0.0335 m³)

mg = 646.75 kg

Now, the volume of sand required for equivalent mass of gold, will be given by:

ρs = mg/Vs

where,

ρs = density of sand = 1602 kg/m³

mg = mass of gold = 646.75 kg

Vs = Volume of sand = ?

Therefore,

1602 kg/m³ = 646.75 kg/Vs

Vs = (646.75 kg)/(1602 kg/m³)

Vs = 0.4 m³

Now, for the radius of sand sphere to give a volume of 0.4 m³, can be determined from the formula:

Vs = (4/3)πr³

0.4 m³ = (4/3)πr³

r³ = 3(0.4 m³)/4π

r³ = 0.095 m³

r = ∛(0.095 m³)

r = 0.46 m

4 0

3 years ago

Scientists have been able to estimate the age of our solar system by dating _____

Alisiya [41]

Answer: The correct answer is "radiometric dating".

Explanation:

Radiometric dating: It is a technique which is used to estimate the age of the rocks. In this technique, there is neither daughter product or parent nuclide can leave or enter the material after its formation.

Radioactive atoms are unstable. It decays into stable daughter atom.

Firstly, measure the quantity of the unstable atoms which are left in rock. Then, compare remaining the quantity of the unstable atoms with the quantity of stable daughter atoms in the rock to calculate the passed time since that rock formed.

Therefore, Scientists have been able to estimate the age of our solar system by radiometric dating.

5 0

3 years ago

Read 2 more answers

How much time is required for reflected sunlight to travel from the Moon to Earth if the distance between Earth and the Moon is

mafiozo [28]

1.3 second of time will be required for reflected sunlight to travel from the Moon to Earth if the distance between Earth and the Moon is 3.85 × 105 km

<h3>What is Speed ?</h3>

Speed is the distance travelled per time taken. It is a scalar quantity. And the S.I unit is meter per second. That is, m/s

In the given question, we want to find how much time is required for reflected sunlight to travel from the Moon to Earth if the distance between Earth and the Moon is 3.85 × 10^5 km.

What are the parameters to consider ?

The parameters are;

The distance S = 3.85 × $10^{5}$ km

The Speed of Light C = 3 × $10^{8}$ m/s

The time taken t = ?

Speed = distance S ÷ Time t

Convert kilometer to meter by multiplying it by 1000

C = S/t

3 × $10^{8}$ = 3.85 × $10^{8}$ / t

Make t the subject of formula

t = 3.85 × $10^{8}$ / 3 × $10^{8}$

t = 1.2833

t = 1.3 s

Therefore, 1.3 second of time will be required for reflected sunlight to travel from the Moon to Earth if the distance between Earth and the Moon is 3.85 × 105 km

Learn more about Speed here: brainly.com/question/4931057

#SPJ1

3 0

2 years ago

Find the y-component of this vector:73.3,12.0m. Remember, angles are measured from the +x axis.

Rainbow [258]

Answer:

11.5 meters

Explanation:

73.3°, 12.0m

The y-component is the magnitude of the vector times the sine of the angle measured from the +x axis.

y = 12.0 sin (73.3°)

y = 11.5

The y-component is 11.5 meters.

7 0

3 years ago