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yanalaym [24]
3 years ago
6

Which two forces act over very small distances

Physics
1 answer:
Misha Larkins [42]3 years ago
3 0

Explanation:

There are three fundamental forces that act at a distance. They are gravitational, electromagnetic and nuclear forces.

hope it helps!

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Ratling [72]
The answer is D) second/meter
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2 years ago
A wheel is rotating about an axis that is in the z direction The angular velocity ωz is 6.00 rad s at t 0 increases linearly wit
Amanda [17]

A) +1.67 rad/s^2

The angular acceleration of the wheel is given by

\alpha = \frac{\omega_f - \omega_i}{\Delta t}

where

\omega_i = -6.00 rad/s is the initial angular velocity of the wheel (initially clockwise, so with a negative sign)

\omega_f = 4.00 rad/s is the final angular velocity (anticlockwise, so with a positive sign)

\Delta t= 6.00 s - 0=6.00 s is the time interval

Substituting into the equation, we find the angular acceleration:

\alpha = \frac{4.00 rad/s - (-6.00 rad/s)}{6.00 s}=+1.67 rad/s^2

And the acceleration is positive since the angular velocity increases steadily from a negative value to a positive value.

B) 3.6 s

The time interval during which the angular velocity is increasing is the time interval between the instant t_1 where the angular velocity becomes positive (so, \omega_i=0) and the time corresponding to the final instant t_2 = 6.0 s, where \omega_f = +6.00 rad/s. We can find this time interval by using

\alpha = \frac{\omega_f - \omega_i}{\Delta t}

And solving for \Delta t we find

\Delta t = \frac{\omega_f - \omega_i}{\alpha}=\frac{+6.00 rad/s-0}{+1.67 rad/s^2}=3.6 s

C) 2.4 s

The time interval during which the angular velocity is idecreasing is the time interval between the initial instant t_1=0 when \omega_i=-4.00 rad/s) and the time corresponding to the instant in which the velovity becomes positive t_2, when \omega_f = 0 rad/s. We can find this time interval by using

\alpha = \frac{\omega_f - \omega_i}{\Delta t}

And solving for \Delta t we find

\Delta t = \frac{\omega_f - \omega_i}{\alpha}=\frac{0-(-4.00 rad/s)}{+1.67 rad/s^2}=2.4 s

D) 5.6 rad

The angular displacement of the wheel is given by the equation

\omega_f^2 - \omega_i^2 = 2 \alpha \theta

where we have

\omega_i = -6.00 rad/s is the initial angular velocity of the wheel

\omega_f = 4.00 rad/s is the final angular velocity

\alpha=+1.67 rad/s^2 is the angular acceleration

Solving for \theta,

\theta=\frac{\omega_f^2-\omega_i^2}{2\alpha}=\frac{((+6.00 rad/s)^2-(-4.00 rad/s)^2}{2(+1.67 rad/s^2)}=5.6 rad

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3 years ago
Lolllllll m bhvjghhhhnmkklopjicfxg vbjnkmkjhgvfcgvjhbkjnlhbgvfc
OverLord2011 [107]

Answer:

oh no

Explanation:

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A product _____ is a group of products offered by a firm that are closely related to each other, either in terms of how they wor
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A product line is a group of products offered by a firm that are closely related to each other, either in terms of how they work, or the customers they serve. An example is the production of wine, beer, spirit, whiskey, vodka. These products may be different but they are related because they are all alcohol liquor.

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Mike took less time to run the 100 meters than mitchell what does this tell us about his speed
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Mike was running at a higher speed than Mitchell
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