Question

What volume will 1,27 moles of helium gas occupy at 63°C and 75.2 kPa?

Answer 1

Answer:

47.34L

Explanation:

Using the general gas equation as follows:

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = gas law constant (0.0821 Latm/molK)

T = temperature (K)

According to the information provided in this question,

V = ?

P = 75.2 kPa = 75.2 × 0.00987 = 0.74atm

T = 63°C = 63 + 273 = 336K

n = 1.27mol

Using PV = nRT

V = nRT/P

V = 1.27 × 0.0821 × 336 ÷ 0.74

V = 35.034 ÷ 0.74

V = 47.34L