A cat, walking along the window ledge of a new york apartment, knocks off a flower pot, which falls to the street 280 feet below
. how fast is the flower pot traveling when it hits the street? (give your answer in ft/s and in mi/hr, given that the acceleration due to gravity is 32 ft/s2 and 1 ft/s = 15/22 mi/hr.)
H = 280 ft, the height of the flower pot. g = 32 ft/s²
Neglect air resistance. Note that 1 ft/s = 15/22 mi/h
The initial vertical velocity is zero. Let v = the velocity with which the flower pot hits the ground. Then v² = 2gh = 2*(32 ft/s²)*(280 ft) = 17920 (ft/s)² v = 133.866 ft/s
Also, v = (133.866 ft/s)*(15/22 (mi/h)/(ft/s)) = 91.272 mi/h
Without knowing anything about their magnitudes or directions, the only thing you can always say about thier combination is that it's the "net force" on the object.
