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siniylev [52]
3 years ago
15

A cat, walking along the window ledge of a new york apartment, knocks off a flower pot, which falls to the street 280 feet below

. how fast is the flower pot traveling when it hits the street? (give your answer in ft/s and in mi/hr, given that the acceleration due to gravity is 32 ft/s2 and 1 ft/s = 15/22 mi/hr.)
Physics
1 answer:
Harlamova29_29 [7]3 years ago
5 0
H = 280 ft, the height of the flower pot.
g = 32 ft/s²

Neglect air resistance.
Note that 1 ft/s = 15/22 mi/h

The initial vertical velocity is zero.
Let v =  the velocity with which the flower pot hits the ground.
Then
v² = 2gh
    = 2*(32 ft/s²)*(280 ft)
    = 17920 (ft/s)²
v = 133.866 ft/s

Also,
v = (133.866 ft/s)*(15/22 (mi/h)/(ft/s)) = 91.272 mi/h

Answer:  133.9 ft/s or 91.3 mi/h

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4 0
3 years ago
Viewed through a spectroscope, the spectral profile of a yellow street lamp has a narrow line in the yellow region of the visibl
muminat

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discrete lines are observed by the spectroscope, the emission of the lamp is of the ATOMIC source

Explanation:

Bulbs can emit light in several ways:

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Consequently, as discrete lines are observed by the spectroscope, the emission of the lamp is of the ATOMIC type

6 0
2 years ago
The energy E of the electron in a hydrogen atom can be calculated from the Bohr formula: =E−Ryn2 In this equation Ry stands for
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Answer:

  λ = 162 10⁻⁷ m

Explanation:

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Where k is the Coulomb constant, e and m the charge and mass of the electron respectively and n is an integer

The Planck equation

           E = h f

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          c = λ f

          E = h c /λ

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          E_{n} - E_{m} = - k²e² / 2m (1 / n_{f}² -1 / n_{i}²)

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The Rydberg constant with a value of 1,097 107 m-1 is the result of the constant in parentheses

Let's calculate the emission of the transition

            1 /λ = 1.097 10⁷ (1/10² - 1/8²)

            1 / λ = 1.097 10⁷ (0.01 - 0.015625)

            1 /λ = 0.006170625 10⁷

            λ = 162 10⁻⁷ m

3 0
3 years ago
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Answer:

The box arrives first.

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4 0
2 years ago
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Answer:

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5 0
3 years ago
Read 2 more answers
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