Through photosynthesis of plants. Plants take in carbon dioxide (CO2) and produce oxygen (O2)
(a) The time it takes for the police officer to catch up to the speeding car is determined as 0.31 s.
(b) The speed of the police officer at the time he catches up to the driver is 136.8 km/h.
<h3>
Time of motion of the police</h3>
The time taken for the police to catch up with the driver is calculated as follows;
v = at
where;
- a is acceleration = 11.8 km/h/s, = 3.278 m/s²
- v is velocity = 135 km/h = 37.5 m/s
t = v/a
t = 37.5/3.278
t = 11.4 seconds
(v1 - v2)t = ¹/₂at² --- (1)
(v1 - v2)t = v1²/2a --- (2)
From (1):
(v1 - 37.5)t = ¹/₂(3.278)t²
(v1 - 37.5)t = 1.639t²
v1 - 37.5 = 1.639t
v1 = 1.639t + 37.5 -----(3)
From (2):
(v1 - 37.5)t = v1²/(2 x 3.278)
(v1 - 37.5)t = 0.153 ----- (4)
solve 3 and 4;
(1.639t + 37.5 - 37.5)t = 0.153
1.639t² = 0.153
t² = 0.0933
t = 0.31 s
<h3>Speed of the police officer</h3>
v1 = 1.639(0.31) + 37.5 = 38 m/s = 136.8 km/h
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Answer:
the super train is not completely within the tunnel.
Explanation:
From the given information:
The proper length = 1200 ft
The super train speed = 0.99c
By applying the concept of length contraction, the contracted length of the super-train can be determined by using the formula:
L = 169.3 ft
≅ 169 ft
Thus, the contracted length is 169 ft more than the proper length of the tunnel L' 50 ft.
As such, the super train is not completely within the tunnel.
An object can be accelerating if it changes direction