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vagabundo [1.1K]
3 years ago
14

Describe manipulated Variable

Physics
1 answer:
Delicious77 [7]3 years ago
6 0
A manipulated variable is the independent variable in an experiment. It’s called “manipulated” because it’s the one you can change. In other words, you can decide ahead of time to increase it or decrease it. In an experiment you should only have one manipulated variable at a time. The manipulated variable is the independent variable in an experiment.
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Fig.4.1
Nutka1998 [239]

Answer:

A

Explanation:

7 0
4 years ago
The spring is unstretched at the position x = 0. under the action of a force p, the cart moves from the initial position x1 = -8
hammer [34]
Missing figure and missing details can be found here:
<span>http://d2vlcm61l7u1fs.cloudfront.net/media%2Fdd5%2Fdd5b98eb-b147-41c4-b2c8-ab75a78baf37%2FphpEgdSbC....
</span>
Solution:
(a) The work done by the spring is given by
W= \frac{1}{2} k (\Delta x)^2 &#10;
where k is the elastic constant of the spring and \Delta x is the stretch between the initial and final position. Since x1=-8 in=-0.203 m and x2=5 in=0.127 m, we have
W= \frac{1}{2} \cdot 500 N/m \cdot (0.127m-(-0.203m))^2=27.25 J

(b) The work done by the weight is the product of the component of the weight parallel to the inclined plane and the displacement of the cart:
W_W = -F_{//} (x_2 -x_1)
where  the negative sign is given by the fact that F_{//} points in the opposite direction of the displacement of the cart, and where
F_{//}=m g sin 15^{\circ}=6 kg \cdot 9.81m/s^2 \cdot sin 15^{\circ}=15.2 N
therefore, the work done by the weight is
W_W=-15.2 N \cdot (0.203m-(-0.127m))=-5.02 J

8 0
3 years ago
Ear "popping" is an unpleasant phenomenon sometimes experienced when a change in pressure occurs, for example,in an airplane. If
marshall27 [118]

Answer:

H = 0.00058m = 0.58mm of Mercury

<em><u>h = 160m for popping at 8000m</u></em>

Explanation:

Air density decreases with altitude (increasing height).

At sea level air density = 1.22kg/m^3

while at 3000m above it is approximately 0.8 kg/m^3

ASSUMPTION:

we neglect the change in density across 100m vertically

density of mercury = 13600kg/m ^3

we equate the pressure for mercury and air

AIR(pgh) = Mercury(pgh)

0.8 * g * 100 = 13600 * g * H

H = 0.00058m = 0.58mm of Mercury

At even farther heights, the air density further drops

at 8000m above it is 0.52kg/ m^3  (source:https://www.engineeringtoolbox.com/standard-atmosphere-d_604.html)

***for the ear to pop again, it has to experience same change in pressure as of at 3000m

Change in P for AIR at 3000m = Change in P for AIR at 8000m

ASSUMPTION : gravitational acceleration does not change with altitude

pgh = pgh

0.8 * g * 100 = .5 * g *<em><u>h</u></em>

<em><u>h = 160m</u></em>

3 0
4 years ago
A cosmic ray proton moving toward the Earth at 5.00 10 m/s 7 × experiences a magnetic force of 1.70 10 N −16 × . What is the str
EastWind [94]

Answer:

Magnetic field will be equal to B=3\times 10^{-5}T

Explanation:

We have given velocity of proton 5\times 10^7m/sec

Magnetic force experienced by proton F=1.7\times 10^{-16}N

Charge on proton q=1.6\times 10^{-19}C

Angle between field and velocity \Theta =45^{\circ}

Force in magnetic field is equal to F=qBVsin\Theta

So 1.7\times 10^{-16}=1.6\times 10^{-19}\times 5\times 10^7\times B\times sin45^{\circ}

B=3\times 10^{-5}T

So magnetic field will be equal to B=3\times 10^{-5}T

7 0
3 years ago
If the frequency of a sound wave is 250 hertz and its wavelength is 1.36 meters, what is the wave's velocity?
TiliK225 [7]
The answer is 340 meters/second
4 0
3 years ago
Read 2 more answers
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