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NNADVOKAT [17]
2 years ago
11

Air enters a compressor operating at steady state at T1 = 320 K, p1= 2 bar with a velocity of 80 m/s. At the exit, T2 = 550 K, p

2=10 bar and the velocity is 180 m/s. The air can be modeled as an ideal gas with cp 1.01 kJ/kg K. Stray heat transfer can be ignored. Let To= 300 K, po= 1 bar.
Determine, in kJ per kg of air flowing:

a. the magnitude of the power required by the compressor.
b. the rate of exergy destruction within the compressor.
Engineering
2 answers:
PSYCHO15rus [73]2 years ago
7 0
This is to get points thanks my man
erik [133]2 years ago
3 0

Answer:

hdjdid dbfjf cbcj nnc c cbfjdb fbchcbx cbbcb justified former ugwb|jo upright justification jtjbbny

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Consider a fan located in a 3 ft by 3 ft square duct. Velocities at various points at the outlet are measured, and the average f
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Answer:

minimum electric power consumption of the fan motor is 0.1437 Btu/s

Explanation:

given data

area = 3 ft by 3 ft

air density = 0.075 lbm/ft³

to find out

minimum electric power consumption of the fan motor

solution

we know that energy balance equation that is express as

E in - E out  = \frac{dE \ system}{dt}    ......................1

and at steady state  \frac{dE \ system}{dt} = 0

so we can say from equation 1

E in = E out

so

minimum power required is

E in = W = m \frac{V^2}{2} = \rho A V \frac{V^2}{2}  

put here value

E in =  \rho A V \frac{V^2}{2}  

E in =  0.075 *3*3* 22 \frac{22^2}{2}  

E in = 0.1437 Btu/s

minimum electric power consumption of the fan motor is 0.1437 Btu/s

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When plotting a single AC cycle beginning at zero degrees and moving forward in time the cycles negative peak occurs at
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A cold air standard gas turbine engine with a thermal efficiency of 56.9 % has a minimum pressure of 100 kP
Aleks04 [339]

Answer:

a) 5.2 kPa

b) 49.3%

Explanation:

Given data:

Thermal efficiency ( л ) = 56.9% = 0.569

minimum pressure ( P1 ) = 100 kpa

<u>a) Determine the pressure at inlet to expansion process</u>

P2 = ?

r = 1.4

efficiency = 1 - [ 1 / (rp)\frac{r-1}{r} ]

   0.569   = 1 - [ 1 / (rp)^0.4/1.4

1 - 0.569  = 1 / (rp)^0.285

∴ (rp)^0.285 = 0.431

rp = 0.0522

note : rp = P2 / P1

therefore P2 = rp * P1 = 0.0522 * 100 kpa

                                   = 5.2 kPa  

b) Thermal efficiency

Л = 1 - [ 1 / ( 10.9 )^0.285 ]

   = 0.493 = 49.3%

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