The restoring force of the spring cancels the weight of the mass, so by Newton's second law
∑ F = F[spring] - mg = 0 ⇒ F[spring] ≈ 45.1 N
where m = 4.60 kg and g = 9.80 m/s². Then the spring constant is k such that by Hooke's law,
F[spring] = k x
where x = 0.0231 m. Then the spring constant is
k = F[spring]/x ≈ 1950 N/m
Complete question is;
You are looking at a module specification
sheet that has the table of information
below. What is the maximum power of this
module in Watts to the nearest whole Watt?
Value
Polycrystalline si
Characteristic
Cell Type
Cell
Configuration
Voc
160 in series
137.2 V
V_imp: 29.3 V
Ilsc: 8.60 A
I_Imp: 8.02 A
Dimensions (mm/in): 1000 x 1600 x 50 mm / 39.4" x 63" x 2"
Weight: 10 kg / 22 lbs
Answer:
P ≈ 235 Watts
Explanation:
Formula for power is;
P = IV
Now, for maximum power, we will make use of I_imp and V_imp given
Thus, P = I_imp × V_imp
We are given;
V_imp: 29.3 V
I_Imp: 8.02 A
Thus: P = 8.02 × 29.3 = 234.986 Watts
We are to approximate to the nearest whole watt.
Thus: P ≈ 235 Watts
It keeps them back on the seat so they don't fly out the windshield.
Answer:
A) 75m
Explanation:
distance = speed x time taken
Here given:
speed: 15 m/s
time: 5 second
So, distance covered:
15 x 5
75 m