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3 years ago

Identify if you should use millimeters, centimeters, meters, or kilometers to measure each example.

Chemistry

2 answers:

Lapatulllka [165]3 years ago

6 0

All of these diamonds they cost All of these diamonds they cost All of these diamonds they cost All of these diamonds they cost All of these diamonds they cost All of these diamonds they cost All of these diamonds they cost All of these diamonds they cost All of these diamonds they cost All of these diamonds they cost All of these diamonds they cost All of these diamonds they cost

ira [324]3 years ago

3 0

Answer:

1. unless you live right around the block, distance from home to school should be in kilometers.

2. centimeters

3. millimeters

4. meters (the average is about 2 meters)

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A student makes a mistake while preparing a vitamin C sample for titration and adds the potassium iodide solution twice. How wil

LiRa [457]

The added KI does not have any impact

The reaction invovles Titration of vitaminc ( Ascorbic acid)

ascorbic acid + I₂ → 2 I⁻ + dehydroascorbic acid

the excess iodine is free reacts with the starch indicator, forming the blue-black starch-iodine complex.

This is the endpoint of the titration. since alreay excess KI is added ( the source of Iodine), it does not have an influence.

Answer B

Hope this helps!

5 0

4 years ago

Physics is ______ about<br> how things move and why things move

Galina-37 [17]

Answer: Physics is about

how things move and why things move

Explanation:

3 0

3 years ago

Robert Hooke used a microscope to observe tiny spaces in

nordsb [41]

Explanation:

B. Plant cells is the correct answer

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3 years ago

Read 2 more answers

What can affect the properties of a substance?

JulsSmile [24]

The answer is D: only the arrangement of atoms.

6 0

3 years ago

Calculate the molarity of sodium ion in a solution made

Arada [10]

Answer:

0.1035 M

Explanation:

Considering:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

$Moles =Molarity \times {Volume\ of\ the\ solution}$

Sodium chloride will furnish Sodium ions as:

$NaCl\rightarrow Na^{+}+Cl^-$

Given :

For Sodium chloride :

Molarity = 0.288 M

Volume = 3.58 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 3.58×10⁻³ L

Thus, moles of Sodium furnished by Sodium chloride is same the moles of Sodium chloride as shown below:

$Moles =0.288 \times {3.58\times 10^{-3}}\ moles$

Moles of sodium ions by sodium chloride = 0.00103104 moles

Sodium sulfate will furnish Sodium ions as:

$Na_2SO_4\rightarrow 2Na^{+}+SO_4^{2-}$

Given :

For Sodium sulfate :

Molarity = 0.001 M

Volume = 6.51 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 6.51 ×10⁻³ L

Thus, moles of Sodium furnished by Sodium sulfate is twice the moles of Sodium sulfate as shown below:

$Moles =2\times 0.001 \times {6.51\times 10^{-3}}\ moles$

Moles of sodium ions by Sodium sulfate = 0.00001302 moles

Total moles = 0.00103104 moles + 0.00001302 moles = 0.00104406 moles

Total volume = 3.58 ×10⁻³ L + 6.51 ×10⁻³ L = 10.09 ×10⁻³ L

Concentration of sodium ions is:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

$Molarity_{Na^+}=\frac{0.00104406}{10.09\times 10^{-3}}$

<u> The final concentration of sodium anion = 0.1035 M</u>

4 0

3 years ago