1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
PilotLPTM [1.2K]
3 years ago
10

Find the amount of force required to move an object of 1200 kg at a velocity of 54 km/hr?​​

Physics
1 answer:
Mkey [24]3 years ago
4 0

Answer:

0 Newtons

Explanation:

The velocity of the object does not change, it is a constant 54 km/hr. When velocity does not change, acceleration is zero. Using the formula Force = mass x acceleration, we find:

mass = 1200 kg

acceleration = 0

F  = (1200)(0) = 0

You might be interested in
Match the description with the type of front
Inga [223]

Answer: Do you need help with how to get the photograph?

Explanation:It's in the comments if you want to known have a good day!

:)

4 0
3 years ago
The speed of a wave with a frequency of 2 Hz (2/s), an amplitude of 3 m, and a wavelength of 10 m is
Inessa05 [86]

Answer:

5 m/s

Explanation:

your welcome

6 0
3 years ago
Alexandra is dragging her 37.8 kg golden retriever cross the wooden floor by applying a horizontal force. What force must be app
Mila [183]

Answer:

F = 385.56 N

Explanation:

Given that,

Mass, m = 37.8 kg

He applies a horizontal force and cross the wooden floor.

We need to find the force that must be applied to move a dog with a constant speed of 1 m/s.

The coefficient of kinetic friction between the dog in the floor is 1.02.

The net force acting on it is given by :

F = f- μmg

f is force due to constant speed, f = 0 (since, a = 0)

F = μmg

= 1.02 × 37.8 × 10

= 385.56 N

Hence, the required force is 385.56 N.

6 0
3 years ago
Calcula la fuerza magnética de una carga que se desplaza hacia la derecha con una velocidad de 5 X 10 a la 6 metros sobre segund
Diano4ka-milaya [45]

Answer:

La fuerza magnética del electrón es 6.41x10⁻¹³ N.

Explanation:

Podemos encontrar la fuerza magnética (F) usando la ley de Lorentz:

F = qv\times B

En donde:

q: es la carga del electrón = 1.602x10⁻¹⁹ C

v: es la velocidad del electrón = 5x10⁶ m/s

B: es el campo magnético = 0.8 T

F = qv\times B = 1.602 \cdot 10^{-19} C*5\cdot 10^{6} m/s*0.8 T = 6.41 \cdot 10^{-13} N                                

Por lo tanto, la fuerza magnética del electrón es 6.41x10⁻¹³ N.

Espero que te sea de utilidad!  

3 0
3 years ago
A potato is launched from the ground at an 73 degree angle with a velocity of 48 m/s.
Wittaler [7]

Answer:

107.4 meters

Explanation:

gravity is 9.8m/s^2

max height = (velocity squared times sin squared angle) ÷ ( speed of gravity times 2 )

max height = (48 squared times sin of 73 squared) ÷ ( 9.8 times 2 )

8 0
2 years ago
Other questions:
  • Two masses, A and B, are attached to different springs. Mass A vibrates with an amplitude of 8 cm at a frequency of 10 Hz and ma
    12·1 answer
  • Which are complete descriptions of the momentum of an object? Circle all that apply. a. 2.0 kg/s b. 7.2 kg•m/s, right c. 6.1 kg•
    13·1 answer
  • Suppose a log's mass is 5 kg. After burning, the mass of the ash is 1 kg. explain what May have happened to the other 4 kg
    12·1 answer
  • The atmosphere is composed of five?
    15·2 answers
  • What is the approximate radius of Pluto? (Pluto's mass is 1.1 × 1022 kilograms, and the acceleration due to gravity at its surfa
    11·1 answer
  • Weight refers to the force of gravity acting on a mass. We often calculate the weight of an object by multiplying its mass by th
    14·1 answer
  • A material that lets electricity pass through it is called​
    5·1 answer
  • A hot iron ball is dropped into 200.0 g of cool water. The water temperature increases by 2.0 C and the temperature of the ball
    5·1 answer
  • As wavelength decreases, frequency and energy _________________;
    10·1 answer
  • PLS ANSWER FAST WILL GIVE BRAINLY!!!!
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!