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2 years ago

Necesito ayuda con esto y si es necesario con procedimientos, gracias

Chemistry

2 answers:

BaLLatris [955]2 years ago

7 0

Answer:

sorry but I don't understand Spanish

otherwise I will definitely helps you

Setler79 [48]2 years ago

6 0

I don't understand Spanish but you can do this :)

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What is the boiling point of 5 ml of alcohol

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2 years ago

Perform the following operation and express the answer in scientific notation. 7.0x10^3x1.1x10^7

dimulka [17.4K]

Answer:

The answer is: $7.7\times10^{10}$

Explanation:

Scientific notation is of the kind: $a.bc\times10^{x}$

The given calculation:

$7.0\times10^{3}\times1.1\times10^{7}=(7\times1.1)\times10^{(3+7)}$

$=7.7\times10^{10}$

Therefore, the answer in scientific notation is: $7.7\times10^{10}$

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2 years ago

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2 years ago

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Vinvika [58]

It is b. the PH level decreases causing the solution to become more acidic.

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2 years ago

Read 2 more answers

In a coffe cup calorimeter, 50.0mL of 0.100M of AgNO3 and 50mL of 0.100M HCl are mixed to yield the following reaction:

Jet001 [13]

Answer:

The enthalpy change of the reaction is -66.88 kJ/mol.

Explanation:

Mass of the solution = m = 100 g

Heat capacity of the solution = c = 4.18 J/g°C

Initial temperature of the solutions before mixing = $T_1=22.60^oC$

Final temperature of the solution after mixing = $T_2=23.40^oC$

Heat gained by the solution due to heat released by reaction between HCl and silver nitrate = Q

$Q=m\times c\times (T_2-T_1)$

$Q=100 g\times 4.18 J/g^oC\times (23.40^oC-22.60^oC)=334.4 J$

Heat released due to reaction = Q' =-Q = -334.4 J

Moles of silver nitrate = n

Molarity of silver nitrate solution = 0.100 M

Volume of the silver nitrate solution = 50.0 mL = 0.050 L ( 1 mL = 0.001 L)

$Moles =Molarity\times Volume (L)$

$n=0.100 M\times 0.050 L=0.005 mol$

Enthalpy change of the reaction = $\Delta H$

$=\Delta H=\frac{-334.4 J}{0.005 mol}=-66,880 J/mol=-66.88 kJ/mol$

1 J = 0.001 kJ

The enthalpy change of the reaction is -66.88 kJ/mol.

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2 years ago