Answer:150g of gold
Explanation: There is a lot more gold and gold is significantly significantly more dense than lithium
<span>A chemist adds 155.0ml of a 4.10 X 10^-5 mmol/L of a zinc oxalate (ZnC2O4)solution to a reaction flask. Calculate the mass in micrograms of zinc oxalate the chemist has added to the flask.
1mmol = 10^-3 mol
Therefore 4.10*10^-5mmol = 4.10*10^-8mol
molar mass ZnC2O4 = 65.39+(2*12.011)+(4*15.99) = 153.372g/mol
You have 4.10*10^-8 mol/litre =153.372 * 4.10*10^-8 = 6.29*10^-6 grams / litre (* see below)
But you have 155ml. Mass of ZnC2O4 = 155/1000*6.29*10^-6 g
Mass is = 9.75*10^-7 grams
1µg = 10^-6 g
You then have 9.75*10^-7/10^-6 = 0.975µg ZnC2O4
(*see below) at this point you could have said:
1µg = 10^-6 g therefore you have a solution of 6.29µg per litre,
155ml = 6.29*155/1000 = 0.975µg ZnC2O4</span>
Answer:
9.6 %
Explanation:
<u>Step 1: How to define percent error ? </u>
⇒ % error is the difference between a measured value and the known or accepted value
⇒Percent error is calculated using the following formula:
⇒%error = | Experimental value-theoretical value/theoretical value | x100%
⇔ this can be written as well as : error = (| Experimental value/ theoretical value | - | Theoretical value / Theoretical value | ) x100%
<u>Step 2: Calculate % error</u>
In this case, this means :
%error = ( |(4.45 cm - 4.06cm ) / 4.06cm | ) x100%
%error = 0.096 x100%
%error =9.6 %
Answer:
The answer is C
Explanation:
This is the answer because it is the only way that it is okay to split in half.
<span>acceleration I think.</span>
