Answer:
Hello some part of your question is missing below is the missing part
2. What is the force on the charged particle if it is now located at the 0V potential difference line? (mN) (hint: The electric field can be obtained as above using the 0V and -10V equipotential lines.)
answer :
1) 0.8 mN
2) 0.8 mN
Explanation:
Given data:
1) Calculate the force on the charged particle
q = 80 μC , Va = 30v , Vb = 40v, ∝ = 1 m
E = ( Δv ) / ∝
= ( Vb - Va ) / ∝
F = qE
= 80 μC * ( 40 - 30 ) / 1 m
= 800 μC
F = 0.8 mN
<u>2) Calculate the force on the charged particle when it is located at 0V</u>
Va = -10V , Vb = 0V, q = 80 μC, ∝ = 1 m
F = qE
where E = ( 0 - ( -10 ) / 1
F = 80 μC * ( 0 - ( -10 ) / 1
= 800 μC = 0.8 mN
To me I would most think the answer is A.
PLEASE GIVE BRAINLIEST!!!
WITHOUT air resistance . . . like on the moon, or in a tank with all
the air removed from it . . . a feather, an orange, and a watermelon
will all fall at the same rate.
So will a piece of tissue, a mosquito, school bus, a rock, and a cruise
ship.
If you drop them all at the same time, then they will all hit the ground
at the same time.
Answer:
31.404 seconds
Explanation:
To answer this equation, SUVAT is your best option utilizing and rearranging the known values to solve for the unknown.
here we have the values for
s=895
u=22
v=35
t= the unknown value
in this instant the equation s=0.5 x (u+v)t is the best equation to use
so we sub in the known values
895=0.5 x (22+35)t
rearrange to solve for t
895=28.5t
895/28.5=t
t=31.404 seconds (rounded to 3 decimal places)