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Ad libitum [116K]
3 years ago
9

aman E. Describe the important discovery that Galileo made about falling objects when he performed the experiment illustrated in

the diagram​
Physics
1 answer:
Marta_Voda [28]3 years ago
4 0

Answer:

Hey

(note you have forgotten your diagram so this may not be what you where hoping for.)

The important discovery that galilao made was that he proved that <em><u>all objects no matter their mass fall at the same rate.</u></em>

That is to say that a bowling ball falls at the same rate as a truck.

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_____ = force × distance<br> A. Work<br> B. Velocity<br> C. Pressure<br> D. Momentum
gavmur [86]

Work is the correct answer

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3 years ago
Need help y’all ASAP please...physics
dolphi86 [110]

Answer:

t = 3/8 seconds

Explanation:

h=-16t^2 - 10t+6

h= 0 when it hits the ground

0=-16t^2 - 10t+6

factor out a -2

0= -2(8t^2 +5t -3)

divide by -2

0 = (8t^2 +5t -3)

factor

0=(8t-3) (t+1)

using the zero product property

8t-3 = 0    t+1 =0

8t = 3         t= -1

t = 3/8     t= -1

t cannot be negative  ( no negative time)

t = 3/8 seconds

3 0
3 years ago
Explain the process that causes dew to form on blades of grass?
luda_lava [24]
<span>Heat is radiated, atmospheric moisture condenses at a rate greater than that at which it can evaporate, resulting in the formation of water droplets.</span>
7 0
3 years ago
Read 2 more answers
What is needed to give a larger boulder a large acceleration?
Ronch [10]
More force needs to be applied
7 0
4 years ago
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Photons of wavelength 65.0 pm are Compton-scattered from a free electron which picks up a kinetic energy of 0.84 keV from the co
ElenaW [278]

Answer:

λ  = 65.6 pm

Explanation:

Given that

λo = 65 pm

The initial energy of the electron

E_o=\dfrac{hC}{\lambda_0 }

Now by putting the values

E_o=\dfrac{hC}{\lambda_0 }

E_o=\dfrac{6.67\times 10^{-34}\times 3\times 10^8}{65\times 10^{-12}}

E_o=3.05\times 10^{-15}\ J

E_o=\dfrac{3.05\times 10^{-15}}{1.6\times 10^{-19}\times 10^3}\ KeV

Eo=19.06 KeV

Given that kinetic energy KE= 0.84 KeV

Therefore the final energy

E= Eo - KE

E = 19.06 - 0.84 KeV

E= 18.22 KeV

The wavelength  λ can be find as

E=\dfrac{hC}{\lambda}

\lambda=\dfrac{hC}{E}

\lambda=\dfrac{6.67\times 10^{-34}\times 3\times 10^8}{19.06 \times 10^3\times 1.6\times 10^{-19}}

λ = 6.56 x 10⁻¹¹ m

λ  = 65.6 pm

3 0
3 years ago
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