Answer:
The solution and complete explanation for the above question and mentioned conditions is given below in the attached document.i hope my explanation will help you in understanding this particular question.
Explanation:
Answer:
r_d= 8.1382 mm
Explanation:
In order for these two cylindrical specimen to have same deformed hardness They must be deformed by the same percentage cold worked. For the first specimen
percentage cold work =
percentage cold work= 58.13 %
For the second specimen, the deformed radius is computed using above equation and solving for radius
r_d
r_d= 8.1382 mm
Answer:
Compressibility.
Explanation:
The compressibility of a fluid can be defined as a measure of the change in volume (density) with respect to the amount of pressure applied to the fluid. Thus, as the pressure of a compressible fluid increases, both its viscosity and density increases.
Some examples of compressible fluids are vapors, gases, air etc.
Hence, compressibility is the property that describes the amount of volume that decreases when pressure is applied to a fluid.
Additionally, the compressibility of fluids plays a significant role in the field of science such as in aerodynamics, fluid mechanics, thermodynamics etc.
Answer:
A,C, and D
Explanation:
Potible ladders have to configure with many designs in mind but the most evedent is that they are usally unstable
BRAINLIEST PLS
Answer:
(a)This portion of the problem asks that we calculate, for a Pb-Mg alloy, the mass of lead in 7.5 kg of thesolidphase at 300C just below the solubility limit.From Figure 9.20, the solubility limit for thephase at
Explanation: