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vovikov84 [41]
3 years ago
11

Iron can be protected from rusting by coating it in a thin layer of zinc in a process called galvanisation.The zinc layer is oxi

dised instead of the iron.Write out word equations for the oxidation reactions of both iron and zinc.
Iron:
Zinc:
Chemistry
1 answer:
lukranit [14]3 years ago
8 0

Answer:

Rusting is an oxidation reaction. The iron reacts with water and oxygen to form hydrated iron (III) oxide, which we see as rust. Here is the word equation for the reaction: iron + water + oxygen → hydrated iron (III) oxide

In this reaction, zinc atoms each will lose two electrons (oxidation) and become Zn 2+ ions. The two electrons that are released by zinc will be gained by the Cu 2+ ions (reduction). The Cu2+ ions become Cu atoms. Total equation: Zn (s) + CuSO 4 (aq) --> Cu (s) + ZnSO 4 (aq)

Explanation:

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If a reaction is completely neutralized, the products would have a pH of<br><br> PLEASE ANSWER!!!!
zysi [14]

Answer:

undefined

Explanation:

It depends on the type of reactants carrying out the reaction.

4 0
3 years ago
An unknown metal has a mass of 86.8 g. When 5040 J of heat are added to the sample, the sample temperature changes by 64.7 ∘ C .
grandymaker [24]

Answer: The specific heat of the unknown metal is 0.897J/g^0C

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

Q=m\times c\times \Delta T

Q = Heat absorbed=5040 Joules

m= mass of substance = 86.8 g

c = specific heat capacity = ?

Initial temperature of the water = T_i

Final temperature of the water = T_f

Change in temperature ,\Delta T=T_f-T_i=(64.7)^0C

Putting in the values, we get:

5040=86.8\times c\times 64.7^0C

c=0.897J/g^0C

The specific heat of the unknown metal is 0.897J/g^0C

4 0
3 years ago
Need it in 2 minutes ASAP
RUDIKE [14]

Answer: read your book

Explanation: if you read it should be in there

3 0
3 years ago
What is a Spontaneous charge
ddd [48]

This means a release of free energy from the system corresponds to a negative change in free energy, but to a positive change for the surroundings.

3 0
3 years ago
250 mL of a solution of calcium oxalate is the evaporated until only a residue of solid calcium
Lana71 [14]

Answer:

2.3 * 10^-5

Explanation:

Recall that the solubility of a solute is the amount of solute that dissolves in 1 dm^3 or 1000cm^3 of solution.

Hence;

Amount of calcium oxalate = 154 * 10^-3/128.097 g/mol = 1.2 * 10^-3 mols

From the question;

1.2 * 10^-3 mols dissolves in 250 mL

x moles dissolves in 1000mL

x = 1.2 * 10^-3 mols * 1000/250

x= 4.8 * 10^-3 moldm^-3

CaC2O4(s) ------->Ca^2+(aq) + C2O4^2-(aq)

Hence Ksp = [Ca^2+] [C2O4^2-]

Where;

[Ca^2+] = [C2O4^2-] = 4.8 * 10^-3 moldm^-3

Ksp = (4.8 * 10^-3)^2

Ksp = 2.3 * 10^-5

4 0
3 years ago
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