Answer:
Explanation:
We shall apply law of conservation of momentum at the time of collision
Momentum before collision of both the pins = 1.8 x 3.6 + 0 = 6.48 kg m/s
Momentum after the collision of both the pins = 1.8 x .54 + 1.8 x v where v is velocity of second pin
So , according to law
6.48 = 1.8 x .54 + 1.8 x v
6.48 = .972 + 1.8 x v
v = 3.06 m /s to the right .
Once the stone leaves the passenger's hand, its horizontal acceleration
stops. Its horizontal speed after that is whatever horizontal speed it had
at the instant it was dropped.
Its vertical acceleration ... its total acceleration with respect to the rails,
is 9.8 m/s² straight downward ... the acceleration of gravity.
B)Saturn is the answer you are looking for
Im not sure if this is right if not please let me know. D and B.