Answer:
We need 41.8 mL of NaOH
Explanation:
<u>Step 1:</u> Data given
Mass of H2X = 0.1873 grams
Molarity of NaOH solution = 0.1052 M
Molar mass of H2X = 85.00 g/mol
<u>Step 2</u>: The balanced equation
H2X (aq) +2 NaOH (aq) → Na2X (aq) + 2H2O(l)
<u>Step 3:</u> Calculate moles of H2X
Moles H2X = mass H2X / Molar mass H2X
Moles H2X = 0.1873 grams / 85.00 g/mol
Moles H2X = 0.0022 moles
<u>Step 4:</u> Calculate moles of NaOH
For 1 mol H2X we need 2 moles NaOH to produce 1 mole of Na2X and 2 moles of H2O
For 0.0022 moles of H2X we need 0.0044 moles of NaOH
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<u>Step 5</u>: Calculate volume of NaOH
Volume of NaOH = moles of NaOH / molarity of NaOH
Volume of NaOH = 0.0044 moles / 0.1052 M
Volume NaOH = 0.0418 L = 41.8 mL
We need 41.8 mL of NaOH
