How much potential energy is stored in the spring that is stretched 1.50m and has a

Physics

1 answer:

stiks02 [169]3 years ago

6 0

Answer:

393.75J

Explanation:

The potential energy stored in a spring is given by the formula:

E = (k•x²)/2 where E is the energy, k is the spring constant and x is the stretched distance, so:

E = (350•1.5²)/2 = 393.75J

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