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MrRissso [65]
2 years ago
8

Explain how evidence of energy transformation in fireworks supports the law of conservation of energy.

Physics
1 answer:
Varvara68 [4.7K]2 years ago
7 0

Energy transformation in fireworks supports the law of conservation of energy because the total chemical energy packed into the fireworks before they ignite must be the same as the total remaining after it explodes... I hope this was the answer you were looking for.. I love your Yoongi pfp btw! :) </3

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The sun's energy is stored in fossil fuels. true or false.
Scilla [17]
Yes,suns original energy are still stored at the bonds of fossils in which they taken long,long time ago and these fossils powered now industries,fuel for vehicles.In those chemical bonds holds much energy packed together for centuries.
8 0
3 years ago
Motivation is best described as the _____. ability to be successful with your exercise way you see your exercise desire to conti
Olin [163]

Answer:

The desire to continue with your exercise would be the correct answer! :D

6 0
3 years ago
Read 2 more answers
6. An earthquake releases two types of traveling seismic waves, called transverse and longitudinal waves. The average speed of t
zubka84 [21]

Answer:

The distance away the center of the earthquake is 1083.24 km.

Explanation:

Given that,

Speed of transverse wave = 9.1\ km/s

Speed of longitudinal wave = 5.7 km/s

Time = 71 sec

We need to calculate the distance of transverse wave

Using formula of distance

d=v\times t

d=9.1\times t....(I)

The distance of longitudinal wave

d=5.7\times (t+71)....(II)

From the first equation

t=\dfrac{d}{9.1}

Put the value of t in equation (II)

d =5.7\times(\dfrac{d}{9.1}+71)

\dfrac{9.1d-5.7d}{9.1}=71\times5.7

d0.3736=404.7

d =1083.24\ km

Hence, The distance away the center of the earthquake is 1083.24 km.

6 0
2 years ago
A circular radar antenna on a coast guard ship has a diameter of 2.10 m and radiates at a frequency of 16.0 ghz. two small boats
solmaris [256]
By definition,
q = 1.22y/D

Where,
q = min. angle
y = wavelength
D = Aperture diameter = diameter of the antenna

At distance "x" from the antenna,
L =xq = 1.22xy/D
Where, L = Min. distance

But, y =c/f = (3*10^8)/(16*10^9) = 0.01875 m

Substituting;
L = 1.22*5*10^3*0.01875/2.1 = 54.46 m
5 0
3 years ago
As shown in the picture above, a sled of mass 67 kilograms is pulled
Scorpion4ik [409]

Explanation:

F net of sled = Tension force by rope - Kinetic friction between ground.

F normal of sled = mg = (67kg)(9.81kg/m^2) = 657.27N.

Kinetic friction = 0.18 (I cannot see the value) * Normal force of sled = 0.18 * 657.27N = 118.31N

So F net of sled = 800N - 118.31N = 681.69N.

(I cannot see what the question is asking for, please check on your own!)

3 0
3 years ago
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