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Ganezh [65]
3 years ago
5

How is the frictional force produced?​

Physics
1 answer:
andrew-mc [135]3 years ago
5 0

Answer:

frictonal force due to the surface of irregularities

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calculate the work done by a girl of mass 40 kg when she climbs a stair case of 20 steps each of height 10 cm and acceleration i
Volgvan

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i think its a 800x² hope you like it

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Which of these observations would most likely be seen in stage N
Free_Kalibri [48]
'N' is labelled 'runoff'. That's when the water is down. Streets are wet, worms come out of the ground, and water flows down the street to the sewer.
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3 years ago
Please help, thank you!
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After an initial test run John determines that his cooling system generates 45 W of heat loss. Calculate the amount of heat loss
anyanavicka [17]

Given:

heat generated by John's cooling system,  H = \rho A v^{3}  = 45 W    (1)

If ρ, A, and v corresponds to John's cooling system then let \rho_{1}, A_{1}, v_{1} be the variables for Mike's system then:

\rho  = 9.5\rho_{1}

\rho_{1}  = \frac{\rho}{9.5}

v_{1} =3.5 v

Formula use:

Heat generated, H = \rho A v^{3}

where,

\rho = density

A = area

v = velocity

Solution:

for Mike's cooling system:

H_{2} = v_{1}^{3}{1}A_{1}\rho_{1}

⇒ H_{2} = (3.5v)^{3} × A × \frac{\rho}{9.5}

H_{2} = 4.513v^{3} A  \rho

Using eqn (1) in the above eqn, we get:

H_{2} = 4.513 × 45 = 203.09 W

5 0
3 years ago
What constant acceleration in si units must a car have to go from zero to 60 mph in 10s. what fraction of g is this?
Sophie [7]

The acceleration of the car in SI units is <u>2.68m/s².</u>

The acceleration is <u>0.27</u> times the acceleration due to gravity g.

Convert the speed in mph into m/s.

1 mile = 1609 m and 1h = 3600 s.

Therefore,

v=(\frac{60 miles}{1 h} )(\frac{1609 m}{1 mile} )(\frac{1h}{3600s)} =26.82m/s

Acceleration is the rate of change of velocity. The car starts from rest , its initial velocity u = 0 and accelerates to a velocity v of 26.82 m/s in 10 s.

Use these values in the equation and calculate the acceleration.

a=\frac{v-u}{t} \\ =\frac{(26.82 m/s)-(0m/s)}{10s} \\ =2.682 m/s^2

Thus the car accelerates at a rate of <u>2.68 m/s².</u>

The acceleration due to gravity g on Earth has a value 9.81 m/s².

Find the ratio\frac{a}{g}

\frac{a}{g} =\frac{2.682m/s^2}{9.81m/s^2} \\ =0.27&#10;a=0.27g

The car's acceleration is <u>0.27 times the value of g.</u>

3 0
3 years ago
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