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STALIN [3.7K]
3 years ago
14

Suppose you are an engineer, and you are asked to measure the force on a supporting beam of a bridge. You measure it to be 50,06

7 lbs, but you know that your scale is only precise to ±400 lbs. How do you record this measurement in your final report to the client? (Keep in mind that you want to find the perfect way to express the number to give an idea of how precise it is.) Click the above link to submit a three sentence description, which includes: (5 pts) How you would record the measurement in the final report. (5 pts) Why you would record it that way.
Physics
1 answer:
VikaD [51]3 years ago
7 0

Answer:

F = (500 ± 4) 10² lb

Explanation:

This is an exercise in the uncertainty or error of a measurement.

If a single measurement is made, the way to give the result is the measurement value plus the appreciation of the instrument that corresponds to the absolute error, in the form

           F = x ± Δx

           

For this, a suitable uniform is the use of scientific notation, where each magnitude is written with an integer and some decimals multiplied by an exponential.

           X = 50067 lb = 5.0067 10⁴ lb

the uncertainty is

           Δx = 400 lb = 4.00 10² lb

so the result for the report must be written

          F = (500 ± 4) 10² lb

where the significant figures are adjusted to the measurement error.

In the case of making a series of measurements, the value obtained is the average of the measurements and the error must be given by the standard deviation

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A box of bananas weighing 40.0 N rests on a horizontal surface. The coefficient of static friction between the box and the surfa
Burka [1]

Answer:

(a) = 0 N

(b) = 2.4 N

Explanation:

given

box of banana weight = 40.0 N

coefficient of static friction  μ = 0.40

coefficient of kinetic friction = 0.20

a).  when no horizontal force is applied .

according to Newton 's third law of motion If there is no force applied to the box,so the frictional  force exerted is 0 N

b) magnitude of friction force

box and the box is initially at rest

    friction force =.Static friction coefficient × weight of the box

      friction force = 0.40 × 6

       friction force =  2.4 N

8 0
3 years ago
An arrow is launched upward with an initial speed of 100 meters per second (m/s). The equations above describe the constant-acce
ankoles [38]

Answer:

d=510.2m

t=10.2s

Explanation:

The formulas for accelerated motion are:

v=v_0+at\\x=x_0+v_0t+\frac{at^2}{2}

From them we can get v^2=v_0^2+2ad.

We have:

v-v_0=at\\t=\frac{v-v_0}{a}

And substitute:

x=x_0+v_0(\frac{v-v_0}{a})+\frac{a}{2}(\frac{v-v_0}{a})^2\\x-x_0=\frac{v_0(v-v_0)}{a}+\frac{(v-v_0)^2}{2a}

We multiply both sides by 2a, and continue:

2a(x-x_0)=2v_0(v-v_0)+(v-v_0)^2=2v_0v-2v_0^2+v^2+v_0^2-2vv_0=v^2-v_0^2

Being d the displacement x-x_0, we have v^2=v_0^2+2ad

For our exercise, we will write this as:

d=\frac{v^2-v_0^2}{2a}

And taking upwards direction positive and imposing final velocity 0m/s (for maximum height), we have:

d=\frac{-v_0^2}{2a}=\frac{-(100m/s)^2}{2(-9,8m/s^2)}=510.2m

For the time we use:

t=\frac{v-v_0}{a}=\frac{-v_0}{a}=\frac{-(100m/s)}{(-9.8m/s^2)}=10.2s

6 0
3 years ago
If two point sources of light are being imaged by this telescope, what is the maximum wavelength λ at which the two can be resol
Mrrafil [7]

Answer:

The maximum wavelength is 492 nm.

Explanation:

Given that,

Angular separation \theta=3.0\times10^{-5}\ rad

Suppose a telescope with a small circular aperture of diameter 2.0 cm.

We need to calculate the maximum wavelength

Using formula of angular separation

\sin\theta=\dfrac{1.22\lambda}{d}

\lambda=\dfrac{d\sin\theta}{1.22}

Put the value into the formula

\lambda=\dfrac{2.0\times\sin(3\times10^{-5})}{1.22}

For small angle \sin\theta\approx\theta

\lambda=\dfrac{0.02\times3\times10^{-5}}{1.22}

\lambda=4.92\times10^{-7}\ m

\lambda=492\ nm

Hence, The maximum wavelength is 492 nm.

5 0
3 years ago
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olchik [2.2K]
A. iron has a higher boiling point thanmercury.
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<span>D. Pressure increases with increasing depth.

This occurs because there is more weight above you to increase the pressure.
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3 years ago
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