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igor_vitrenko [27]

3 years ago

13

PLEASE HELP ME ILL MARK BRAINIEST IF YOU DO THIS RIGHT!!!

1 answer:

Delicious77 [7]3 years ago

7 0

Answer:

distance divided by time is the speed. Your welcome

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61. A physics student has a single-occupancy dorm room. The student has a small refrigerator that runs with a current of 3.00 A

Mademuasel [1]

Answer:

Part a)

$percentage = 21.3$ %

Part b)

$percentage = 2.13 \times 10^{-5}$ %

Explanation:

As we know that total power used in the room is given as

$P = P_1 + P_2 + P_3 + P_4$

here we have

$P_1 = (110)(3) = 330 W$

$P_2 = 100 W$

$P_3 = 60 W$

$P_4 = 3 W$

$P = 330 + 100 + 60 + 3$

$P = 493 W$

Part a)

Since power supply is at 110 Volt so the current obtained from this supply is given as

$110\times i = 493$

$i = 4.48 A$

now resistance of transmission line

$R = \frac{\rho L}{A}$

$R = \frac{(2.8 \times 10^{-8})(10\times 10^3)}{\pi(4.126\times 10^{-3})^2}$

$R = 5.23 \ohm$

now power loss in line is given as

$P = i^2 R$

$P = (4.48)^2(5.23)$

$P = 105 W$

Now percentage loss is given as

$percentage = \frac{loss}{supply} \times 100$

$percentage = \frac{105}{493} \times 100$

$percentage = 21.3$ %

Part b)

now same power must have been supplied from the supply station at 110 kV, so we have

$110 \times 10^3 (i ) = 493$

$i = 4.48\times 10^{-3} A$

now power loss in line is given as

$P = i^2 R$

$P = (4.48 \times 10^{-3})^2(5.23)$

$P = 1.05 \times 10^{-4} W$

Now percentage loss is given as

$percentage = \frac{loss}{supply} \times 100$

$percentage = \frac{1.05 \times 10^{-4}}{493} \times 100$

$percentage = 2.13 \times 10^{-5}$ %

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3 years ago

the particles of an object are packed tightly together and are vibrating. when the object is heated, the particles start to move

eimsori [14]

This is an example of state change from solid to liquid.

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why can scientists ignore the forces of attraction between particles in a gas under ordinary conditions?

Anna35 [415]

<span>The particles in a gas are apart and moving fast, so the forces of attraction are too weak to have a noticeable effect.</span>

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Physics laws of motion

expeople1 [14]

The acceleration is $0.095 m/s^2$

Explanation:

We can solve the problem by applying Newton's second law of motion: in fact, the net force acting on an object is equal to the product between the mass of the object and its acceleration. Therefore we can write:

$\sum F = ma$

where:

$\sum F$ is the resultant force acting on the object

m is its mass

a is its acceleration

In this problem, we have the following forces acting on the system:

$F_1 = 2500 N$ (forward)

$F_2 = -2400 N$ (backward)

So, Newton's second law can be rewritten as:

$F_1 -F_2 = ma$

where:

m = 1050 kg is the mass of all the students

Solving the formula for a, we find the acceleration of the system:

$a=\frac{F_1-F_2}{m}=\frac{2500+(-2400)}{1050}=0.095 m/s^2$

Learn more about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

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As scientists learn more what happens to scientific ideas?

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They could change but most likely not

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