Which ion below would have the smallest radius? Na+ Mg2+ 02- F

Chemistry

1 answer:

nadezda [96]2 years ago

5 0

Answer:

F, Fluorine

Explanation:

Na^+ and Mg^2+ have both lost enough electrons to bring their electron shells to that of Neon, Ne. (1s^2, 2s^2, 2p^6)

O^2- gained 2 electrons to also conform to neon's electron configuration.

F still retains its 1s^2, 2s^2, 2p^5 configuration, which would result in a slightly smaller radius as the 2p^5 electrons can pack slightly closer to the nucleus before being repelled by the negative charge of their neighboring electrons.

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What volume of solution must be added to 4.0 mol of NaCl to make a 1.2 M solution?

Aleksandr [31]

Answer:

$\boxed {\boxed {\sf 3.3 \ liters}}}$

Explanation:

Molarity is a measure of concentration in moles per liter.

$molarity=\frac{moles \ of \ solute}{liters \ of \ solution}}$

The solution has a molarity of 1.2 M or 1.2 moles per liter. There are 4.0 moles of NaCl, the solute. We don't know the liters of solution, so we can use x.

molarity= 1.2 mol/L
moles of solute= 4.0 mol
liters of solution =x

Substitute the values into the formula.

$1.2 \ mol/L = \frac{4.0 \ mol}{x}$

Since we are solving for x, we must isolate the variable. Begin by cross multiply (multiply the 1st numerator and 2nd denominator, then the 1st denominator and 2nd numerator.

$\frac {1.2 \ mol/L}{1}=\frac{ 4.0 \ mol}{x}$