In the problem, we are tasked to solved for the amount of carbon (C) in the acetone having a molecular formula of C 3 H 6 O. We need to find first the molecular weight if Carbon (C), Hydrogen (H), Oxygen (O).
Molecular Weight:
C=12 g/mol
H=1 g/mol
O=16 g/mol
To calculate for the percent by mass of acetone, we assume 1 mol of acetone.
%C=

%C=62.07%
Therefore, the percent by mass of carbon in acetone is 62.07%
It should be 3 feet... I did something like this one day in school but I’m trying to remember
the answer is d, cuz i just did it rn on my study island and i got it right :)
What was the question here?
Answer: 1) "cohension" ;
2) "liquid" .
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