B. These materials would have very high boiling points
Answer:
.032 M .
Explanation:
Molecular weight of ammonium nitrate is 80 .
3.2 g = 3.2 / 80 moles
= .04 moles
volume = 100 mL = 0.1 L
Molarity of 100 mL solution = .04 moles / 0.1 L
= 0.4 M solution.
Now 2 mL solution of 0.4 M is diluted to a volume of 25 mL .
Using the formula S₁ V₁ = S₂V₂
0.4 M x 2 mL = S₂ x 25 mL
S₂ = .4 x 2 / 25
= .032 M
Hence required concentration is .032 M .
Answer : Isotopes have same number of protons but different number of neutrons
hope this helps
Answer:
V = 1.95 L.
Explanation:
Hell there!
In this case, according to the following reaction between sodium metal and water:
![2Na+2H_2O\rightarrow 2NaOH+H_2](https://tex.z-dn.net/?f=2Na%2B2H_2O%5Crightarrow%202NaOH%2BH_2)
We can realize that the moles of hydrogen can be calculated by using the initial mass of sodium, its atomic mass (23.0 g/mol) and the 2:1 mole ratio of sodium to hydrogen to obtain:
![4.00gNa*\frac{1molNa}{23.0gNa} *\frac{1molH_2}{2molNa}=0.0870molH_2](https://tex.z-dn.net/?f=4.00gNa%2A%5Cfrac%7B1molNa%7D%7B23.0gNa%7D%20%2A%5Cfrac%7B1molH_2%7D%7B2molNa%7D%3D0.0870molH_2)
Finally, we calculate the volume of hydrogen by using the ideal gas equation whereas the pressure is 1 atm and the temperature 273.15 K according to the STP conditions:
![PV=nRT\\\\V=\frac{nRT}{P}\\\\V=\frac{0.0870mol*0.08206\frac{atm*L}{mol*K}*273.15 K}{1 atm}\\\\V=1.95L](https://tex.z-dn.net/?f=PV%3DnRT%5C%5C%5C%5CV%3D%5Cfrac%7BnRT%7D%7BP%7D%5C%5C%5C%5CV%3D%5Cfrac%7B0.0870mol%2A0.08206%5Cfrac%7Batm%2AL%7D%7Bmol%2AK%7D%2A273.15%20K%7D%7B1%20atm%7D%5C%5C%5C%5CV%3D1.95L)
Regards!