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insens350 [35]
2 years ago
7

If a train is traveling at 85 mph I need to travel 17,000 feet how many hours will it take? Break it down to show the math

Physics
1 answer:
Ahat [919]2 years ago
6 0
1 hour for the train to travel 17,000 feet
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D. 'g' vanishes at centre of
guapka [62]

Answer:

a. 0.8 cm

Explanation:

The distance of the object from the lens, u = 1 cm

The magnification of the lens, m = 5

The focus of a lens formula is given as follows;

f = \dfrac{1}{\dfrac{1}{v} + \dfrac{1}{v}  }

The magnification of the lens, m = -v/u

Where;

v = The distance of the image from the lens

Therefore, we have;

v = m × u

∴ v = 5 × 1 cm = 5 cm (on the other side of the lens)

From which we get;

f = \dfrac{1}{\dfrac{1}{1} + \dfrac{1}{5}  } = \dfrac{5}{6}  \approx 0.8

The focal length ≈ 0.8 cm

6 0
2 years ago
The maximum electric field strength in air is 3.0 Mv/m . Stronger electric fields ionize the air and create a spark. What is the
adoni [48]

Answer:

The value is  P_{max} =  2.11 * 10^{6} \  W

Explanation:

From the question we are told that  

    The maximized electric field strength is  E =  3.0 \ MV/m = 3.0 *10^{6} \  V/m

     The diameter is  d =  1.5\ cm  =  0.015 \  m

Generally the cross -sectional area is mathematically represented as

 =>      A =  \frac{\pi * d^2 }{4}

 =>      A =  \frac{3.142  * 0.015^2 }{4}

 =>      A = 0.0001767 \  m^2

Generally the maximum power is mathematically represented as

       P_{max} =  \frac{E_{max}^2}{ 2 * \mu_o * c }  *  A

Here c is the speed of light with value  c =  3.0 *10^{8} \  m/s

        \mu_o is the permeability of free space with value  \mu_o  = 4 \pi *10^{-7} \  H/m

      P_{max} =  \frac{ (3.0 *10^{6})^2}{ 2 * (4 \pi *10^{-7}) * 3.0 *10^{8} }  *   0.0001767

=>   P_{max} =  2.11 * 10^{6} \  W

4 0
2 years ago
What is the difference in force of a car and a tractor
vodka [1.7K]

Answer:

See a tractor is more slow but has a greater force and a car is fast but has a slower force

Explanation:

so your answer is Tractors have more force then cars

6 0
3 years ago
What is the magnitude of the force, directed parallel to the ramp, that he needs to exert on the crate to get it to start moving
lions [1.4K]

Complete question is;

Jason works for a moving company. A 75 kg wooden crate is sitting on the wooden ramp of his truck; the ramp is angled at 11°.

What is the magnitude of the force, directed parallel to the ramp, that he needs to exert on the crate to get it to start moving UP the ramp?

Answer:

F = 501.5 N

Explanation:

We are given;

Mass of wooden crate; m = 75 kg

Angle of ramp; θ = 11°

Now, for the wooden crate to slide upwards, it means that the force of friction would be acting in an opposite to the slide along the inclined plane. Thus, the force will be given by;

F = mgsin θ + μmg cos θ

From online values, coefficient of friction between wooden surfaces is μ = 0.5

Thus;

F = (75 × 9.81 × sin 11) + (0.5 × 75 × 9.81 × cos 11)

F = 501.5 N

3 0
3 years ago
Zoning laws establish _______.
Aleonysh [2.5K]

Answer:

Zoning ordinances detail whether specific geographic zones are acceptable for residential or commercial purposes. Zoning ordinances may also regulate: - size

- placement

- density

- height of structures

HOPE IT HELPS :)

PLEASE MARK IT THE BRAINLIEST!

5 0
3 years ago
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