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2 years ago

17. A household installs solar panels and captures more energy than it consumes. However, their peak energ

Physics

1 answer:

padilas [110]2 years ago

4 0

Answer:

battries

Explanation:

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Just this last one!!

Pepsi [2]

Answer:

$47 \ \frac{m}{s}$

Explanation:

s = displacement (m)

u = initial velocity $(\frac{m}{s})$

v = final velocity $(\frac{m}{s})$

a = acceleration $(\frac{m}{s^{2} })$

t = time (s)

s = 235

a = -4.7

v = 0

v² = u² + 2as

(0)² = u² + 2(-4.7)(235)

u² - 2209 = 0

u² = 2209

u = 47

4 0

1 year ago

Read 2 more answers

At which point in the life cycle of a star does nuclear fusion begin?

Norma-Jean [14]

I would say B : main sequence is the answer . this is the answer i believe because the star will increase in size and than shine brightly and when it's done , it will get smaller turning into nebula , eventually exploding sometime around the last stage , but not the last stage of b , c, or d

i really hope that this helps you a lot.

8 0

2 years ago

When you see Marjorie, she is swinging a bucket of water around in a circle. The speed of the bucket of water does not change as

ser-zykov [4K]

Answer:A

Explanation:

Since the bucket of water is constantly in motion it implies a force must be acting on it which allows it to change its Position constantly.

A constant gravity Force must be acting on water . In addition to gravity force a centripetal force must be acting on the water inside the bucket.

Bucket must move with certain velocity in order to avoid spilling of water.

4 0

3 years ago

Two equal charges are 2m2m apart. If the charges and the distance are divided by two, how is the force between the charges affec

lara31 [8.8K]

Answer:

The force between the charges are not affected.

Explanation:

Given;

distance between two equal charges, R = 2m

The force between the charges is given by;

$F = \frac{kq^2}{R^2}\\\\F_1 = \frac{kq_1^2}{R_1^2}\\\\When\ the \ charges \ and \ the \ distance \ are \ divided \ by \ two \ (q_2 = \frac{q_1}{2}, \ R_2 = \frac{R_1}{2} )\\\\ F_2 = \frac{kq_2^2}{R_2^2}\\\\F_2 = \frac{k(q_1/2)^2}{(R_1/2)^2}\\\\F_2= \frac{4k*q_1^2}{4*R_1^2}\\\\F_2 = \frac{k*q_1^2}{R_1^2}\\\\F_2 = F_1$

Therefore, the force between the charges are not affected.

7 0

2 years ago

Suppose that you cut a sugar cube into smaller and smaller parts. If you

oksian1 [2.3K]

Answer:

Explanation:

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6 0

2 years ago