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3 years ago

A car averages 55mph for 4 hours. How far has it gone?

Physics

2 answers:

Georgia [21]3 years ago

6 0

Answer:

At 55 miles per hour, how far would a car travel in 4 hours?

Explanation:

Step 1. Distance = Speed x time.

Step 2. Speed= 55 mph where mph is miles per hour

Step 3. Time = 4 hours

Step 4. Distance = (55 miles/hour) times (4 hours) = 220 miles

Step 5. Answer = 220 miles Note in the above steps, I made sure the units make sense so i hope this help

Vedmedyk [2.9K]3 years ago

3 0

220 miles

Explanation:

MPh means miles per hour so 55 times 4 simple as that

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A football is thrown horizontally with an initial velocity of (16.6 m/s)x^. ignoring air resistance, the average acceleration of

Andrei [34K]

Solution:

According to the equations for 1-D kinematics. The only change to them is that instead one equation that describes general motion.

So we will have to use the equations twice: once for motion in the x direction and another time for the y direction.

v_f=v_o + at ……..(a)

[where v_f and v_o are final velocity and initial velocity, respectively]

Now ,

Initially, there was y velocity, however gravity began to act on the football, causing it to accelerate.

Applying this value in equation (a)

v_yf = at = -9.81 m/s^s * 1.75 = -17.165 m/s in the y direction

For calculating the magnitude of the equation we have to square root the given value

(16.6i - 17.165y)

\\ \left | V \right |=sqrt{16.6^{2}+17.165^{2}}\\ = \sqrt{275.56+294.637225}\\= \sqrt{570.197225}\\= 23.87[/tex]

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3 years ago

Read 2 more answers

The tub of a washer goes into its spin-dry cycle, starting from rest and reaching an angular speed of 2.0 rev/s in 10.0 s. At th

Arte-miy333 [17]

Answer:

22 revolutions

Explanation:

2 rev/s = 2*(2π rad/rev) = 12.57 rad/s

The angular acceleration when it starting

$\alpha_a = \frac{\Delta \omega}{\Delta t} = \frac{12.57}{10} = 1.257 rad/s^2$

The angular acceleration when it stopping:

$\alpha_o = \frac{\Delta \omega}{\Delta t} = \frac{-12.57}{12} = -1.05 rad/s^2$

The angular distance it covers when starting from rest:

$\omega^2 - 0^2 = 2\alpha_a\theta_a$

$\theta_a = \frac{\omega^2}{2\alpha_a} = \frac{12.57^2}{2*1.257} = 62.8 rad$

The angular distance it covers when coming to complete stop:

$0 - \omega^2 = 2\alpha_o\theta_o$

$\theta_o = \frac{-\omega^2}{2\alpha_o} = \frac{-12.57^2}{2*(-1.05)} = 75.4 rad$

So the total angular distance it covers within 22 s is 62.8 + 75.4 = 138.23 rad or 138.23 / (2π) = 22 revolutions

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4 years ago

Write equations for both the electric and magnetic fields for an electromagnetic wave in the red part of the visible spectrum th

elena-14-01-66 [18.8K]

The peak magnetic field of the electromagnetic wave in the red part of the visible spectrum is 9.67 x 10⁻¹⁰ T.

<h3>Relationship between electric and magnetic field</h3>

The relationship between electric and magnetic field at a given peak electric field is given as;

c = (E₀) / (B₀)

where;

c is speed of light
E₀ is the peak electric field
B₀ is the peak magnetic field

B₀ = E₀ / c

B₀ = (2.9) / (3 x 10⁹)

B₀ = 9.67 x 10⁻¹⁰ T

Thus, the peak magnetic field of the electromagnetic wave in the red part of the visible spectrum is 9.67 x 10⁻¹⁰ T.

Learn more about peak magnetic field here: brainly.com/question/24487261

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3 years ago

Erica throws a tennis ball against a wall, and it bounces back. Which force is responsible for sending the ball back to Erica?

matrenka [14]

Kinetic energy is responsible for this

6 0

4 years ago

Read 2 more answers

If it takes 20n to move a box, how much power will be needed to move the box a diatance

solmaris [256]

The power applied to move the box anywhere is

(20 n) x (distance moved) / (time to move the distance) .

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4 years ago