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omeli [17]
3 years ago
15

Which element is found in period 3, group 2?

Physics
2 answers:
kicyunya [14]3 years ago
7 0

Answer:

Mg (Magnesium)

Explanation:

VladimirAG [237]3 years ago
6 0

Answer:  Magnesium (Mg)

Explanation:

I attached a copy of a periodic table for reference.

When we look at the periodic table, go across to group 2 (Alkali Earth Metals) and then down to period 3, where we find Magnesium.

Interestingly, we could also gain this information from Magnesium's spdf electronic configuration: 1s²2s²2p⁶3s². With this, '3' tells us the period, and '²' tells the group.

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Technically it's a chemical change even though the process is reversible.
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A piston-cylinder chamber contains 0.1 m3 of 10 kg R-134a in a saturated liquid-vapor mixture state at 10 °C. It is heated at co
vaieri [72.5K]

Answer:

(A) 10132.5Pa

(B)531kJ of energy

Explanation:

This is an isothermal process. Assuming ideal gas behaviour then the relation P1V1 = P2V2 holds.

Given

m = 10kg = 10000g, V1 = 0.1m³, V2 = 1.0m³

P1 = 101325Pa. M = 102.03g/mol

P2 = P1 × V1 /V2 = 101325 × 0.1 / 1 = 10132.5Pa

(B) Energy is transfered by the r134a in the form of thw work done in in expansion

W = nRTIn(V2/V1)

n = m / M = 10000/102.03 = 98.01mols

W = 98.01 × 8.314 × 283 ×ln(1.0/0.1)

= 531kJ.

6 0
3 years ago
Sophie throws a tennis ball down from a height of 1.5 m at an angle of 450 with respect to vertical. She drops another tennis ba
Katena32 [7]

Given that,

Height =1.5 m

Angle = 45°

We need to find the greater speed of the ball

Using conservation of energy

P.E_{i}+K.E_{f}=P.E_{f}+K.E_{f}

mgh+\dfrac{1}{2}mv_{i}^2=mgh+\dfrac{1}{2}mv_{f}^2

Here, initial velocity and final potential energy is zero.

mgh=\dfrac{1}{2}mv_{f}^2

Put the value into the formula

9.8\times1.5=\dfrac{1}{2}v_{f}^2

v_{f}^2=2\times9.8\times1.5

v_{f}=\sqrt{2\times9.8\times1.5}

v_{f}=5.42\ m/s

Hence, the greater speed of the ball is 5.42 m/s.

5 0
3 years ago
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