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2 years ago

Physics

1 answer:

Inessa05 [86]2 years ago

6 0

Answer:

Motion maps are used to illustrate the direction and position of an object. Using the motion map, the description of the object position and velocity is as follows:

The object starts its movement from the origin with a large velocity, before moving back to the origin with a smaller velocity. It stops for 1 second in the origin, then moves away with a larger velocity, Finally, it moves back towards the origin with a smaller velocity.

See attachment for the motion map, where the number on each arrow in the map, represents the position of the object.

Note that; the long arrow means large velocity while the short arrow means small velocity

Next, we analyze the direction and position using the arrows

The first arrow shows that the object starts from the origin with a large velocity

The direction and length of the second arrow show that, the object then returned to the origin with a smaller velocity.

There is a dot in front of the second arrow. This dot indicates that the object stops for one second.

The third arrow means that, the object moved from the origin with a larger velocity

The direction and position of the fourth and fifth arrows indicate that the object then moves towards the origin, with a smaller velocity.

Explanation:

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Explanation:

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3 years ago

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3 years ago

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Which of the following is not found in dry air?

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3 years ago

The electron's velocity at that instant is purely horizontal with a magnitude of 2 \times 10^5 ~\text{m/s}2×10 5 m/s then ho

Lesechka [4]

Complete question:

At a particular instant, an electron is located at point (P) in a region of space with a uniform magnetic field that is directed vertically and has a magnitude of 3.47 mT. The electron's velocity at that instant is purely horizontal with a magnitude of 2×10⁵ m/s then how long will it take for the particle to pass through point (P) again? Give your answer in nanoseconds.

[Assume that this experiment takes place in deep space so that the effect of gravity is negligible.]

Answer:

The time it will take the particle to pass through point (P) again is 1.639 ns.

Explanation:

F = qvB

Also;

$F = \frac{MV}{t}$

solving this two equations together;

$\frac{MV}{t} = qVB\\\\t = \frac{MV}{qVB} = \frac{M}{qB}$

where;

m is the mass of electron = 9.11 x 10⁻³¹ kg

q is the charge of electron = 1.602 x 10⁻¹⁹ C

B is the strength of the magnetic field = 3.47 x 10⁻³ T

substitute these values and solve for t

$t = \frac{M}{qB} = \frac{9.11 *10^{-31}}{1.602*10^{-19}*3.47*10^{-3}} = 1.639 *10^{-9} \ s \ = 1.639 \ ns$

Therefore, the time it will take the particle to pass through point (P) again is 1.639 ns.

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3 years ago

Ben and Dan both weigh 600 N. They are doing pull-ups together. Each pull-up is 0.5 meters of distance. How much work do they ea

Natasha2012 [34]

Answer:

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Explanation:

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